答案 0 :(得分:0)
正确,这是逻辑,用NAND取代NOT(foo和bar)(foo,bar) 注意,在步骤5中,我们通过对步骤4中的表达式应用NOT NOT来获得NAND
1. NOT X AND Z OR NOT Y AND Z
2. Z AND (NOT X OR NOT Y) by Distributive property of AND
3. Z AND NOT (X AND Y) by DeMorgan
4. Z AND NAND(X,Y)
5. NOT (NOT (Z AND NAND(X,Y)))
6. NOT NAND(Z, NAND(X,Y))