我没有找到关于这个主题的任何内容,但我是在生动地做梦,还是可以在PHP中扫描PNG图像并找到图片中的透明位置?
例如,如果有一个带有透明孔的电视的图像,屏幕就是。我可以通过扫描Alpha通道找到透明像素的最左上角,最右上角,最左下角,最右下角的坐标吗?
不确定是否有图书馆这样做,我检查得很快但没找到..
答案 0 :(得分:0)
也许不是最优雅的解决方案,我确信有更好的方法,但这适用于格式良好的png图像
// Returns the coordinates of a transparent rectangle in a PNG file (top left, top right, lower left, lower right
public function getTransparentRectangleCoordinates($fileUrl)
{
define ('TRANSPARENCY_THRESHOLD', 100); // 127=fully transparent, 0=black
$img = @imagecreatefrompng($fileUrl);
if (!$img) return ('Invalid PNG Image');
$coordLowestX = array(imagesx($img), '');
$coordHighestX = array(0, '');
$coordLowestY = array('', imagesy($img));
$coordHighestY = array('', 0);
$minX = imagesx($img);
$maxX = 0;
$minY = imagesy($img);
$maxY = 0;
// Scanning image pixels to find transparent points
for ($x=0; $x < imagesx($img); ++$x)
{
for ($y=0; $y < imagesy($img); ++$y)
{
$alpha = (imagecolorat($img, $x, $y) >> 24) & 0xFF;
if ($alpha >= TRANSPARENCY_THRESHOLD)
{
if ($x < $coordLowestX[0]) $coordLowestX = array($x, $y);
if ($x > $coordHighestX[0]) $coordHighestX = array($x, $y);
if ($y < $coordLowestY[1]) $coordLowestY = array($x, $y);
if ($y >= $coordHighestY[1]) $coordHighestY = array($x, $y);
if ($x < $minX) $minX = $x;
if ($x > $maxX) $maxX = $x;
if ($y < $minY) $minY = $y;
if ($y > $maxY) $maxY = $y;
}
}
}
// This means it's a non-rotated rectangle
if ( $coordLowestX == array($minX, $minY) )
{
$isRotated = false;
return array( array($minX, $minY), array($maxX, $minY), array($minX, $maxY), array($maxX, $maxY) );
}
// This means it's a rotated rectangle
else
{
$isRotated = true;
// Rotated counter-clockwise
if ($coordLowestX[1] < $coordHighestX[1])
return array($coordLowestX, $coordLowestY, $coordHighestY, $coordHighestX);
else // Rotated clockwise
return array($coordLowestY, $coordHighestY, $coordLowestX, $coordHighestX);
}
}