Question

我有这个数组：

Array
(
    [images] => Array
        (
            [0] => g
            [1] => hp
        )

    [g] => Array
        (
            [0] => menu
            [1] => submenu
            [2] => icons
        )

    [hp] => Array
        (
            [0] => cat
            [1] => icons
            [2] => banners
        )

    [menu] => Array
        (
            [0] => v1
        )

    [submenu] => Array
        (
            [0] => img
            [1] => icons
        )

    [icons] => Array
        (
            [0] => v1
        )

    [cat] => Array
        (
            [0] => kt
            [1] => hk
            [2] => bm
            [3] => w
            [4] => m
            [5] => at
            [6] => e
        )

    [banners] => Array
        (
            [0] => v1
        )

    [img] => Array
        (
            [0] => e
        )

    [kt] => Array
        (
            [0] => v1
        )

    [hk] => Array
        (
            [0] => v1
        )

    [bm] => Array
        (
            [0] => v1
        )

    [w] => Array
        (
            [0] => v1
        )

    [m] => Array
        (
            [0] => v1
        )

    [at] => Array
        (
            [0] => v1
        )

    [e] => Array
        (
            [0] => v1
        )

)

此处images是主文件夹。我想构造这个数组的所有可能路径，从images开始作为第一个subArray，如果任何值作为元素存在于数组本身，它也是一个subFolder我想要经历并做同样的事情，直到我构建所有可能的路径。

所以一些可能的路径是：

images/g/menu/v1
images/g/submenu/img/e/v1

请问g images中的值是g中的值，但也存在于数组本身中。所以我通过menu并且menu，它再次存在于数组中。同样再次查看v1的每个值images/g/menu/v1，这在数组中不存在。所以构造的路径是：subject_list= ['this should work1', '[0000] Unhandled exception in Unknown - class something::something', 'this should work2', '[0001] URGENT: something is not working', '[0002] subject: something / all users combined into 1', 'this should work3'] description_list = ['1', '2', '3'] for i in subject_list: try: fls = open(i + ".txt", 'w') fls.writelines('') fls.close() except Exception as a: print(a) pass。

Answer 1

可能有更好的方法，但这应该可以解决问题：

//php mysql while 
      If ($rrows['user_level'] == 1) {?>
    //html code
    }?>

输出：

while ($rrows = mysql_fetch_array($rs_results)){

      if ($rrows['user_level'] == 1){
         // display as previously

如何从数组构造所有可能的路径？

1 个答案: