Question

我在尝试运行这个程序时遇到了一些问题我正在努力...要求说我不允许使用排序功能......我自己做了一些事情......等等。

差不多，程序编译但执行后挂起......我猜它已陷入无限循环......但我似乎无法找到它...... :(

该程序读取已经被排序最少的数据文件并将它们（有序）合并到第三个.txt文件中......

这两个文件是Data1.txt和Data2.txt 包含：

DATA1.TXT

Data2.txt

combine.c

#include <stdio.h>
#include <stdlib.h>


void sortData(FILE *fpData1, FILE *fpData2)
{

 int n, m; 
 FILE *fpMerge;


 fpMerge = fopen("Merge.txt", "w+");


 fscanf(fpData2, "%i", &n);
 fscanf(fpData1, "%i", &m);
 while(n != EOF || m != EOF)
 {

  if(n == EOF)
  {
   fscanf(fpData1, "%i", &m);

   while(m != EOF)
   {

    fprintf(fpMerge, "%i\n", m);
    fscanf(fpData1, "%i", &m);
   }
  }
  if(m == EOF)
  {
   fscanf(fpData2, "%i", &n);

   while(n != EOF)
   {

    fprintf(fpMerge, "%i\n", n);
    fscanf(fpData2, "%i", &n);
   }

  }

  if(n < m)
  {
   fprintf(fpMerge, "%i\n", n);
   fscanf(fpData2, "%i", &n);
  }
  if(n > m)
  {
   fprintf(fpMerge, "%i\n", m);
   fscanf(fpData1, "%i", &m);
  }
  if(n == m)
  {
   fprintf(fpMerge, "%i\n", n); 
   fprintf(fpMerge, "%i\n", m);
   fscanf(fpData2, "%i", &n);
   fscanf(fpData1, "%i", &m);

  }
 }

 fclose(fpMerge);
}

int main (void)
{
 FILE *fpData1;
 FILE *fpData2;


 fpData1 = fopen("Data1.txt", "r");
 if(fpData1 == NULL)
 {
  printf("There was an error opening the file...program terminating..\n");
  exit(1);
 }

 fpData2 = fopen("Data2.txt", "r");
 if(fpData2 == NULL)
 {
  printf("There was an error opening the file...program terminating..\n");
  exit(1);
 }



 sortData(fpData1, fpData2);


 fclose(fpData1);
 fclose(fpData2); 

 return 0;
}

Answer 1

您不想比较n != EOF，而是fscanf的返回值：

int count_1;
count_1 = fscanf(fpData1, "%i", &m);
if (count_1 == EOF) // EOF (or error)
{
  // ...
}

fscanf也会在出错时返回EOF。如果您需要分开EOF和错误条件，请使用ferror(fpData1)，然后查找错误代码（存储在errno中）。

Answer 2

您对EOF的测试不太正确

void sortData(FILE *fpData1, FILE *fpData2)
{
    int data1;
    int data2; 
    FILE *fpMerge;

    fpMerge = fopen("Merge.txt", "w+");
    fscanf(fpData1, "%i", &data1);
    fscanf(fpData2, "%i", &data2);

    // While one file still has data        
    while(!feof(fpData1) && !feof(fpData2))
    {
        // Choose 1 file to test
        // Read from that file and put into merge file until either we
        // run out of data or the condition fails.
        if(data1 < data2)
        {
            do {fprintf(fpMerge, "%i\n", data1);}
            while ((fscanf(fpData1, "%i", &data1) != 0) && (data1 <= data2));
        }
        else
        {
            do {fprintf(fpMerge, "%i\n", data2);}
            while ((fscanf(fpData2, "%i", &data2) != 0) && (data2 <= data1));
        }
        // NOTE: if fscanf() returns 0 it has failed to read (EOF)
    }
    // One of the files has reached the EOF
    // Dump the other file.
    while(fscanf(fpData1, "%i", &data1) != 0) {fprintf(fpMerge, "%i\n", data1);}
    while(fscanf(fpData2, "%i", &data2) != 0) {fprintf(fpMerge, "%i\n", data2);}
}

Answer 3

EOF 不是角色。
EOF 不是整数。
任何文件都不会包含 EOF （char和int）。

EOF 是一个条件文件将处于该条件或（通常）不是。

您应该检查fscanf()的返回值以检测 EOF 或其他问题。

C程序合并文件没有找到EOF，陷入无限循环！

3 个答案: