Question

我正在编写这个python程序，一切正常但是当我运行它时，我陷入无限循环。我如何解决它？谢谢。

import sys
def main():
    name = input("Enter your name:")
    ssn = input("Enter your Social Security Number:")
    income = eval(input("Enter your net income:"))

    while income <= 0:
        print("Error, then net income you entered is less than zero! Try again.")
        income = eval(input("Enter your net income again:"))

    while income > 0:
        net = calc(income, name, ssn)

def calc(income, name, ssn):
    if income > 15000.00:
        tax = .05 * (income - 15000.00)
        print(tax)
        print(name)
        print(ssn)
        sys.exit
    elif income > 30000.00:
        tax = .1 * (income - 30000.00)
        print(tax)
        print(name)
        print(ssn)
        sys.exit
    else:
        print("There is no tax to be paid, income is in the first $15000.00")
        print(name)
        print(ssn)
        sys.exit
main()

Answer 1

sys.exit是一个功能。您需要调用它（sys.exit()）来退出脚本。

Answer 2

不需要在main（）中的第二个。接下来就是＆＃34; sys.exit＆＃34;是不对的，你必须写＆＃34; sys.exit（）＆＃34;。在你的calc（）函数中你应该替换if＆＃34;如果收入＆gt; 15000.00：＆＃34;与＆＃34;如果收入＆gt; 15000.00和收入＆lt; = 30000：＆＃34;或者elif案件永远不会被考虑。

这里有正确的代码：

import sys

def main():
    name = input("Enter your name:")
    ssn = input("Enter your Social Security Number:")
    income = eval(input("Enter your net income:"))
    while income <= 0:
        print("Error, then net income you entered is less than zero! Try again.")
        income = eval(input("Enter your net income again:"))
    net = calc(income, name, ssn)

def calc(income, name, ssn):
    if income > 15000.00 and income <= 30000:
        tax = .05 * (income - 15000.00)
        print(tax)
        print(name)
        print(ssn)
        sys.exit()
    elif income > 30000.00:
        tax = .1 * (income - 30000.00)
        print(tax)
        print(name)
        print(ssn)
        sys.exit()
    else:
        print("There is no tax to be paid, income is in the first $15000.00")
        print(name)
        print(ssn)
        sys.exit()
main()

python，陷入无限循环程序

2 个答案: