Question

我在这里看不到问题。

当我调用一个条目时，我陷入无限循环。

我正在做wcf，所以我的服务器工作正常。这是我的客户。如果我把循环拿出来，一切都有效。但我需要这些菜单。所以我知道我的代码是正确的，但我的循环不是。

看不出我出错的地方。

class Client
{
    static void Main(string[] args)
    {
        try
        {
            BikeReference.BikeSalesClient bikeRef = new BikeClient.BikeReference.BikeSalesClient();
            String menu = "\n\nEnter:\n" +
                "0 to get all the bike stock;\n" +
                "1 to get all the bike types;\n" +
                // ...
                "8 to quit:\n";

            Console.WriteLine(menu);

            // will throw FormatException if not int
            int entry = int.Parse(Console.ReadLine());

            do
            {
                switch (entry)
                {
                    case 0:
                        foreach (var obj in bikeRef.GetAllBikeStock())
                        {
                            Console.WriteLine("");
                            Console.WriteLine("Bike ID: {0}", obj.IdBikeStock);
                            Console.WriteLine("Bike Type ID: {0}", obj.IdBikeType);
                            // ...
                            Console.WriteLine("Sold: {0}", obj.isItSold);
                            //break;
                        }
                        break;

                    case 1:
                        Console.WriteLine(bikeRef.UpdateBikeStock(15));
                        break;

                    default:
                        Console.WriteLine("Unrecognised option...");
                        break;
                }
            }
            while (entry != 7);
        }

        catch (Exception)//(Exception e)
        {
           // Console.WriteLine("{0} Exception caught.", e);
        }
    }
}

Answer 1

在循环中更改您的入口变量

int entry = 0; //Init
do
{
    Console.WriteLine(menu);

    // will throw FormatException if not int
    entry = int.Parse(Console.ReadLine());
    ...
} while (entry != 7);

Answer 2

在循环内部，您不会修改变量“entry”。因此，除非您的第一个条目= 7，否则您将陷入循环，因为(entry != 7)它始终是while (entry != 7);

在entry = int.Parse(Console.ReadLine());之前添加行switch (entry)这样你就可以继续询问“条目”，因为条目可能等于7.因此，退出循环。

    int entry;

    do
    {  
        Console.WriteLine(menu);

        entry = int.Parse(Console.ReadLine());
        switch (entry)
        //...
   }while (entry != 7);

Answer 3

如上所述，您必须更改循环内的entry变量：

    class Client
{
    static void Main(string[] args)
    {
        try
        {
            BikeReference.BikeSalesClient bikeRef = new BikeClient.BikeReference.BikeSalesClient();
            String menu = "\n\nEnter:\n" +
                "0 to get all the bike stock;\n" +
                "1 to get all the bike types;\n" +
                // ...
                "8 to quit:\n";

            Console.WriteLine(menu);

                // will throw FormatException if not int
                int entry = int.Parse(Console.ReadLine());

            do
            {
                switch (entry)
                {
                    case 0:
                        foreach (var obj in bikeRef.GetAllBikeStock())
                        {
                            Console.WriteLine("");
                            Console.WriteLine("Bike ID: {0}", obj.IdBikeStock);
                            Console.WriteLine("Bike Type ID: {0}", obj.IdBikeType);
                            // ...
                            Console.WriteLine("Sold: {0}", obj.isItSold);
                            //break;
                        }
                        break;

                    case 1:
                        Console.WriteLine(bikeRef.UpdateBikeStock(15));
                        break;

                    default:
                        Console.WriteLine("Unrecognised option...");
                        break;
                }
            entry = int.Parse(Console.ReadLine());
            }
            while (entry != 7);
        }

        catch (Exception)//(Exception e)
        {
           // Console.WriteLine("{0} Exception caught.", e);
        }
    }
}

Answer 4

切换后必须等待输入。否则该条目不能成为！= 7

陷入无限循环

4 个答案: