我一直致力于制作一个可以在多个实例中使用的解码器,只需更改输入/输出向量大小的通用值即可。解码器将“输出”单个位,基于输入的整数转换的多个位置。解码器本身工作正常。当我做一个测试工作台并编译时,问题就出现了。导致:
错误(10482):DECODER.vhd(41)处的VHDL错误:使用了对象“n”但未声明
我在下面添加了模型和测试平台:
LIBRARY IEEE;
USE IEEE.std_logic_1164.ALL;
USE IEEE.numeric_std.ALL;
ENTITY DECODER IS
--GENERIC (delay : delay_length := 0 ns);
GENERIC (n : POSITIVE := 2);
PORT (a : IN std_logic_vector(n-1 DOWNTO 0);
x : OUT std_logic_vector(2**n-1 DOWNTO 0));
END ENTITY DECODER;
ARCHITECTURE dflow OF DECODER IS
CONSTANT x_out : BIT_VECTOR (2**n-1 DOWNTO 0) :=
( 0 => '1', OTHERS => '0');
BEGIN
x <= to_stdlogicvector(x_out sll to_integer(unsigned(a)));
END ARCHITECTURE dflow;
--test bench----------------------------------------
LIBRARY IEEE;
USE IEEE.std_logic_1164.ALL;
USE IEEE.numeric_std.ALL;
ENTITY TN2 IS
END ENTITY TN2;
ARCHITECTURE IO_TN2 OF TN2 IS
COMPONENT DECODER IS
--GENERIC (delay : delay_length := 0 ns);
GENERIC (n : POSITIVE := 2);
PORT (a : IN std_logic_vector(n-1 DOWNTO 0);
x : OUT std_logic_vector(2**n-1 DOWNTO 0));
END COMPONENT DECODER;
SIGNAL a : std_logic_vector (n-1 DOWNTO 0); --<-- USED BUT NOT DECLARED
SIGNAL x : std_logic_vector (2**n-1 DOWNTO 0);
BEGIN
G1 : DECODER
GENERIC MAP (n => 2)
PORT MAP (a,x);
a <= "00", "01" AFTER 1 NS, "10" AFTER 2 NS, "11" AFTER 3 NS,
"00" AFTER 4 NS, "0Z" AFTER 5 NS;
END ARCHITECTURE IO_TN2;
CONFIGURATION CFG_DECODER OF TN2 IS
FOR IO_TN2
FOR G1 : DECODER
USE ENTITY work.DECODER(dflow)
GENERIC MAP (n => 2)
PORT MAP (a,x);
END FOR;
END FOR;
END CONFIGURATION CFG_DECODER;
编译器告诉我我没有声明n,我认为我在组件声明中做了。我应该在哪里申报? 第二个问题是如何声明多个泛型,即 1个delay_length的通用 1个通用的n 我尝试在模型实体中放入2个泛型语句,但编译器并不认为这是正确的做法。
总是非常感谢你的帮助。 d
答案 0 :(得分:2)
您的组件声明声明存在名为decoder
的组件,该组件(以及此组件的其他属性)具有名为n
的通用组件,默认值为2
。此时,在分析文件时,您没有说明要分配给n
的实际值。
我的方法是在声明组件之前定义一个常量:
constant DECODER_WIDTH : integer := 2;
然后使用它来声明您的信号:
SIGNAL a : std_logic_vector (DECODER_WIDTH-1 downto 0);
当您实例化decoder
时,您还将n
泛型绑定到此常量:
G1 : DECODER
GENERIC MAP (n => DECODER_WIDTH)
PORT MAP (a,x);
如果您确实需要更改n
的值,则必须在包中声明DECODER_WIDTH
常量,然后此文件将use
TN2
实体声明,以及配置语句之前。如果您不需要配置来更改解码器大小,那么您可以从配置语句中省略generic map
。
答案 1 :(得分:0)
感谢您的评论我已经使用您建议的修改更新了以下代码,并且效果很好
--test bench for 2/4 decoder----------------------------------------
LIBRARY IEEE;
USE IEEE.std_logic_1164.ALL;
USE IEEE.numeric_std.ALL;
ENTITY TN2 IS
END ENTITY TN2;
ARCHITECTURE IO_TN2 OF TN2 IS
COMPONENT DECODER IS
--GENERIC (delay : delay_length := 0 ns);
GENERIC (n : POSITIVE := 2);
PORT (a : IN std_logic_vector(n-1 DOWNTO 0);
x : OUT std_logic_vector(2**n-1 DOWNTO 0));
END COMPONENT DECODER;
CONSTANT DECODER_WIDTH : integer := 2; ---<-- ADDED constant changing this value will alter decoder vector size
SIGNAL a : std_logic_vector (DECODER_WIDTH-1 downto 0); --< changed n to decoder_width
SIGNAL x : std_logic_vector (2**DECODER_WIDTH-1 DOWNTO 0); --< changed n to decoder_width
BEGIN
G1 : DECODER
GENERIC MAP (n => DECODER_WIDTH) --< pass decoder_width to n
PORT MAP (a,x);
a <= "00", "01" AFTER 1 NS, "10" AFTER 2 NS, "11" AFTER 3 NS,
"00" AFTER 4 NS, "0Z" AFTER 5 NS;
END ARCHITECTURE IO_TN2;
CONFIGURATION CFG_DECODER OF TN2 IS
FOR IO_TN2
FOR G1 : DECODER
USE ENTITY work.DECODER(dflow)
GENERIC MAP (n => decoder_width)
PORT MAP (a,x);
END FOR;
END FOR;
END CONFIGURATION CFG_DECODER;