我正在尝试运行我在网上获取的代码,但它在某种程度上测试平台无法在GHDL上运行预期的输出。
架构代码 图书馆IEEE; 使用IEEE.STD_LOGIC_1164.ALL;
entity clk200Hz is
Port (
clk_in : in STD_LOGIC;
reset : in STD_LOGIC;
clk_out: out STD_LOGIC
);
end clk200Hz;
architecture Behavioral of clk200Hz is
signal temporal: STD_LOGIC;
signal counter : integer range 0 to 124999 := 0;
begin
frequency_divider: process (reset, clk_in) begin
if (reset = '1') then
temporal <= '0';
counter <= 0;
elsif rising_edge(clk_in) then
if (counter = 124999) then
temporal <= NOT(temporal);
counter <= 0;
else
counter <= counter + 1;
end if;
end if;
end process;
clk_out <= temporal;
end Behavioral;
试验台:
LIBRARY ieee;
USE ieee.std_logic_1164.ALL;
ENTITY clk200Hz_tb IS
END clk200Hz_tb;
ARCHITECTURE behavior OF clk200Hz_tb IS
COMPONENT clk200Hz
PORT(
clk_in : IN std_logic;
reset : IN std_logic;
clk_out: OUT std_logic
);
END COMPONENT;
-- Inputs
signal clk_in : std_logic := '0';
signal reset : std_logic := '0';
-- Outputs
signal clk_out : std_logic;
constant clk_in_t : time := 20 ns;
BEGIN
-- Instance of unit under test.
uut: clk200Hz PORT MAP (
clk_in => clk_in,
reset => reset,
clk_out => clk_out
);
-- Clock definition.
entrada_process :process
begin
clk_in <= '0';
wait for clk_in_t / 2;
clk_in <= '1';
wait for clk_in_t / 2;
end process;
-- Processing.
stimuli: process
begin
reset <= '1'; -- Initial conditions.
wait for 100 ns;
reset <= '0'; -- Down to work!
wait;
end process;
END;
我预计会形成一个时钟上下波动的波,但情况似乎并非如此。我想知道这个设计有什么问题。
我运行了以下命令:
ghdl -s *.vhd
ghdl -a *.vhd
ghdl -e clk200Hz_tb
ghdl -r clk200Hz_tb --vcd=led.vcd
gtkwave led.vcd
这是我的输出
但是对于时钟输出,我期望一个上下信号,而不是0的信号。
由于