我在素食主义者中使用adonis功能来确定1)如果多个位点的共同宿主物种的微生物群落不同,2)如果站点不同。我已经检查了CV和SO上的所有帖子,并且没有明确的答案如何使用adonis函数确定多个因素的重要性。
我是第一次这样做的,正如Vegan adonis unbalanced design SS type II or III所建议的那样:
## where jacc is a dissimilarity matrix using the jaccard metric
adonis <- adonis(jacc ~ Species + Site, data = df_compare)
# Call:
# adonis(formula = jacc ~ Species + Site, data = df_compare)
#
# Permutation: free
# Number of permutations: 999
#
# Terms added sequentially (first to last)
#
# Df SumsOfSqs MeanSqs F.Model R2 Pr(>F)
# Species 2 0.6055 0.30273 1.7690 0.04981 0.004 **
# Site 4 2.1378 0.53445 3.1231 0.17587 0.001 ***
# Residuals 55 9.4122 0.17113 0.77432
# Total 61 12.1554 1.00000
# ---
# Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
然后颠倒顺序
adonis_2 <- adonis(jacc ~ Site + Species, data = df_compare)
# Call:
# adonis(formula = jacc ~ Site + Species, data = df_compare)
#
# Permutation: free
# Number of permutations: 999
#
# Terms added sequentially (first to last)
#
# Df SumsOfSqs MeanSqs F.Model R2 Pr(>F)
# Site 4 2.4385 0.60962 3.5623 0.20061 0.001 ***
# Species 2 0.3048 0.15238 0.8904 0.02507 0.716
# Residuals 55 9.4122 0.17113 0.77432
# Total 61 12.1554 1.00000
# ---
# Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
但我不知道如何解释,因为顺序很重要,我不确定物种之间是否存在差异
经过一番搜索,我决定使用分层。
我认为这是说:当你只比较同一地点的物种时,共生物种是不同的。
species_adonis <- adonis(jacc ~ Species, strata = df_compare$Site, data = df_compare)
# Call:
# adonis(formula = jacc ~ Species, data = df_compare, strata = df_compare$Site)
#
# Blocks: strata
# Permutation: free
# Number of permutations: 999
#
# Terms added sequentially (first to last)
#
# Df SumsOfSqs MeanSqs F.Model R2 Pr(>F)
# Species 2 0.6055 0.30273 1.5464 0.04981 0.335
# Residuals 59 11.5500 0.19576 0.95019
# Total 61 12.1554 1.00000
然后问关于网站的问题,我在阻塞中使用了物种
我认为这是说:当你只比较相同的物种时,网站是不同的
site_adonis <- adonis(jacc ~ Site, strata = df_compare$Species, data = df_compare)
# Call:
# adonis(formula = jacc ~ Site, data = df_compare, strata = df_compare$Species)
#
# Blocks: strata
# Permutation: free
# Number of permutations: 999
#
# Terms added sequentially (first to last)
#
# Df SumsOfSqs MeanSqs F.Model R2 Pr(>F)
# Site 4 2.4385 0.60962 3.5761 0.20061 0.001 ***
# Residuals 57 9.7169 0.17047 0.79939
# Total 61 12.1554 1.00000
# ---
# Signif. codes: 0 ‘***’ 0.001 ‘**’ 0.01 ‘*’ 0.05 ‘.’ 0.1 ‘ ’ 1
我的结论是,特定物种的微生物群落在不同地点之间存在差异,但微生物群落在宿主物种中没有差异。
我的方法是正确的还是我误解了阶层的使用(即阻塞)?
当我切换变量的顺序时,有没有办法以某种方式平均两个测试中的p值?