ImageJ - 累积直方图和直方图

时间:2015-09-09 14:40:55

标签: java image-processing histogram imagej

我的程序遇到了一个小问题,因为它似乎无法在直方图中找到最高值来计算直方图所应的比例,所以现在整个直方图已超出范围

我真的希望有人可以帮助我,因为它让我发疯了

import ij.*;
import ij.process.*;
import ij.gui.*;
import java.awt.*;
import ij.plugin.filter.*;

public class Oblig3_Oppg2 implements PlugInFilter {

    public int setup(String arg, ImagePlus im) {;
        return DOES_8G + NO_CHANGES;
    }

    public void run(ImageProcessor ip) {
        final int W = 256;
        final int H = 100;
        final int H1 = 140;
        int[] hist = ip.getHistogram();
        int[] KH = new int[W]; //Cumulative Histogram Array


        int maxVal;

        //Calculates the highest pixel count in the Histogram

        for (int i = 0; i < W; i++){
            if (hist[i] > maxVal){
                maxVal = i;
            }
        }

        KH[0] = hist[0];

        for(int i = 1; i < W; i++) {
            KH[i] = KH[i-1] + hist[i];
        }

        ImageProcessor histIp = new ByteProcessor(W, H1);
        histIp.setValue(255);
        histIp.fill();

        int max = KH[255];


        for(int j = 0; j < W; j++){
            KH[j] = (KH[j]*100)/max;  //Scales the Cumulative Histogram
            hist[j] = (hist[j]*100)/maxVal; // Scales the Histogram
        }

        for (int k = 0; k < W; k++){
            histIp.setValue(0);
            histIp.drawLine(k, H, k, H-KH[k]);
        }

        for (int k = 0; k < W; k++){
            histIp.setValue(0);
            histIp.drawLine(k, H, k, H-hist[k]);
        }

        for (int l = 0; l < W; l++){
            histIp.setValue(l);
            histIp.drawLine(l, 140, l, 102);
        }
        histIp.setValue(0);
        histIp.drawLine(W, H, W, 0);

        // Display the histogram image:

        String hTitle = "Histogram";
        ImagePlus histIm = new ImagePlus(hTitle, histIp);
        histIm.show();

    }

}

1 个答案:

答案 0 :(得分:3)

您应该将maxVal设置为实际的,而不是循环中的当前索引

for (int i = 0; i < W; i++){
    if (hist[i] > maxVal){
        maxVal = hist[i]; // <-- here
    }
}

此外,最好将循环限制为hist.length而不是W。如果您将W设置为与ip.getHistogram()返回的数组长度不同的某个值,则可以防止出现错误。

由于您没有提供可运行的示例(即整个Java类;我假设您实现了ij.plugin.filter.PlugInFilter),我没有测试代码,并且它并不完全向我明确你想要达到的目标。