Question

#Heres到目前为止我所拥有的。 colorCircle（myTurtle）似乎不起作用，我真的不知道该怎么做。有点业余，任何提示都将不胜感激。

def drawPolygon(myTurtle,sideLength,numSides):
    turnAngle = 360/numSides
    for i in range(numSides):
        myTurtle.forward(sideLength)
        myTurtle.right(turnAngle)

def drawCircle(myTurtle,radius):
    circumference = 2 * 3.1415 * radius
    sideLength = circumference / 360
    drawPolygon(myTurtle, sideLength, 360)

def colorCircle(myTurtle):
    x = random.random()
    y = random.random()
    myTurtle.up()
    myTurtle.goto(x,y)
    myTurtle.down()
    radius = random.random()
    color = [('white',0),('yellow',1),('green',2),('blue',3),('purple',4),('red',5),('black',6),('magenta',7),('pink',8),('brown',9)]
    random.randint(0,9)
    myTurtle.begin_fill(color)
    drawCircle(myTurtle)

Answer 1

此：

color = [('white',0),('yellow',1),('green',2),('blue',3),('purple',4),('red',5),('black',6),('magenta',7),('pink',8),('brown',9)]

random.randint(0,9)
myTurtle.begin_fill(color)

相当于：

color = [('white',0),('yellow',1),('green',2),('blue',3),('purple',4),('red',5),('black',6),('magenta',7),('pink',8),('brown',9)]

4
myTurtle.begin_fill(color)

因为您没有将随机数分配给变量，例子中为4，所以随机数被丢弃。然后将整个颜色列表作为参数传递给begin_fill（）。

要获得随机颜色，您可以这样做：

colors = ['white', 'yellow'....]  #Note the change here.
rand_num = random.randint(0,9)
selected_color = colors[rand_num]

但是，python使事情easier比那个：

import random

colors = ['white', 'yellow'....]
selected_color = random.choice(colors)  #Pick a random element from the colors list

编辑：=============

但是，您尝试将参数传递给begin_fill()函数，但begin_fill()不接受任何参数。默认情况下，begin_fill()使用黑色作为填充颜色。要将填充颜色设置为其他颜色，请使用以下功能之一：

fill_color('red')  #Sets fill color.
color('red')       #Sets both pen and fill color.

以下是您可以做的一些示例：

import turtle
import random

def drawPolygon(myTurtle,sideLength,numSides):
    turnAngle = 360/numSides
    for i in range(numSides):
        myTurtle.forward(sideLength)
        myTurtle.right(turnAngle)

def drawCircle(myTurtle, radius, fill_color="blue"):
    circumference = 2 * 3.1415 * radius
    sideLength = circumference / 360
    myTurtle.color(fill_color) #color() sets pen and fill color

    myTurtle.begin_fill()  #The next shape that is drawn will be filled.
    drawPolygon(myTurtle, sideLength, 360)
    myTurtle.end_fill()  #Disable filling.

def getRandomColor():
    colors = ['yellow', 'green', 'blue']
    rand_color = random.choice(colors)
    return rand_color


rand_color = getRandomColor()
drawCircle(turtle, 40, rand_color)
turtle.exitonclick()

或者你可以这样做：

import turtle
import random

def drawPolygon(myTurtle,sideLength,numSides):
    turnAngle = 360/numSides
    for i in range(numSides):
        myTurtle.forward(sideLength)
        myTurtle.right(turnAngle)

def getRandomColor():
    colors = ['yellow', 'green', 'blue']
    rand_color = random.choice(colors)
    return rand_color

def drawCircle(myTurtle, radius):
    circumference = 2 * 3.1415 * radius
    sideLength = circumference / 360

    rand_color = getRandomColor()
    myTurtle.color(rand_color) #color() sets pen and fill color

    myTurtle.begin_fill()
    drawPolygon(myTurtle, sideLength, 360)
    myTurtle.end_fill()

drawCircle(turtle, 40)
turtle.exitonclick()

<强> ===========

最后，颜色不是列表的好名称。列表名称应为复数，例如：颜色，数字，单词;然后你可以编写如下所示的循环：

for color in colors:
    ...

for number in numbers:
    ...

for word in words:
    ...

Answer 2

首先，您不能将随机数分配给任何内容

random.randint(0,9) 
#You just say okay give me random number from 0 to 9 and then don't do anything with it

第二个问题是您无法填写begin_fill(color)，但您可以输入begin_fill()，但默认填充颜色为黑色。所以你需要做的是这样的事情：
color = [('white',0),('yellow',1),('green',2),('blue',3),('purple',4),('red',5),('black',6),('magenta',7),('pink',8),('brown',9)] randomPos = random.randint(0,9) #We randomly choose which color will it be myTurtle.fill_color(color[ randomPos ]) #We set fill color to color we previously chose myTurtle.begin_fill() #We start to fill

我希望我有所帮助，如果您有任何疑问，请问我。

Python：尝试在随机点上创建一个圆，具有随机半径，随机填充一组给定的颜色。坚持颜色部分

2 个答案: