Question

我将以下XML（以缩写形式显示）加载到XDocument对象中。

<employees>
  <employee>
    <identification>
      <firstName>John</firstName>
      <lastName>Smith</lastName>
    </identification>
    <payment contractType="1">
      <income type="4" startDate="2014-10-01" endDate="2014-10-31">
      </income>
    </payment>
  </employee>
  <employee>
    <identification>
      <firstName>John</firstName>
      <lastName>Balmer</lastName>
    </identification>
    <payment contractType="2">
      <income type="2" startDate="2014-10-01" endDate="2014-10-31">
      </income>              
    </payment>
  </employee>
</employees>

我想在我的XDocument对象上应用linq查询，该对象基于<lastname>然后<firstname>使用Linq to XML对所有节点进行排序。因此，在应用linq之后，我的XDocument对象将包含以下XML：

<employees>
  <employee>
    <identification>
      <firstName>John</firstName>
      <lastName>Balmer</lastName>
    </identification>
    <payment contractType="2">
      <income type="2" startDate="2014-10-01" endDate="2014-10-31">
      </income>
    </payment>
  </employee>
  <employee>
    <identification>
      <firstName>John</firstName>
      <lastName>Smith</lastName>
    </identification>
    <payment contractType="1">
      <income type="4" startDate="2014-10-01" endDate="2014-10-31">
      </income>              
    </payment>
  </employee>
</employees>

Answer 1

快速又脏，只是为了给你一个想法：

var sorted = new XDocument(
                new XElement(
                   "employees",
                   ORIGINAL_XDOC.Descendants("employee")
                                .OrderBy(e => e.Descendants("lastName")
                                               .Single()
                                               .Value)
                                .ThenBy(e => e.Descendants("firstName")
                                              .Single()
                                              .Value)));

Answer 2

// Extract "employee" Xelements in order.
var orderedEmployees = 
    from employee in xml.Descendants("employee")
    orderby employee.Element("identification").Element("lastName").Value,
            employee.Element("identification").Element("firstName").Value
    select employee;

// Build a new Xelement with the original root and orderded "employee" elements.
var result = new XElement(xml.Root.Name,
                 from employee in orderedEmployees
                 select new XElement(employee)
             );

根据孙子对XDocument的元素进行排序

2 个答案: