我有以下XML，我希望“action”节点基于属性值“no”排序。
<game gamecode="10065904">
<general>
<startdate>2015-06-10 07:59:04</startdate>
<players>
<player seat="1" name="player1" chips="2,937" dealer="1" win="0" bet="20" rebuy="0" addon="0" reg_code="-" />
<player seat="3" name="ponda22c" chips="780" dealer="0" win="0" bet="0" rebuy="0" addon="0" reg_code="-" />
<player seat="5" name="Mesut1Rebel" chips="0" dealer="0" win="0" bet="0" rebuy="0" addon="0" reg_code="-" />
<player seat="6" name="player4" chips="10,746" dealer="0" win="0" bet="420" rebuy="0" addon="0" reg_code="-" />
<player seat="8" name="player5" chips="3,670" dealer="0" win="0" bet="420" rebuy="0" addon="0" reg_code="-" />
<player seat="10" name="player6" chips="5,143" dealer="0" win="2,558" bet="1,700" rebuy="0" addon="0" reg_code="-" />
</players>
</general>
<round no="0">
<action no="1" player="player4" type="1" sum="10" cards="[cards]" />
<action no="2" player="player5" type="2" sum="20" cards="[cards]" />
</round>
<round no="1">
<cards type="Pocket" player="player1">X X</cards>
<action no="4" player="player1" type="3" sum="20" cards="" />
<cards type="Pocket" player="player4">X X</cards>
<action no="5" player="player4" type="3" sum="10" cards="" />
<cards type="Pocket" player="player5">X X</cards>
<action no="6" player="player5" type="4" sum="0" cards="" />
<cards type="Pocket" player="player6">X X</cards>
<action no="3" player="player6" type="3" sum="20" cards="" />
</round>
<round no="2">
<cards type="Flop" player="">H4 CQ C8</cards>
<action no="10" player="player1" type="0" sum="0" cards="" />
<action no="7" player="player4" type="4" sum="0" cards="" />
<action no="11" player="player4" type="3" sum="80" cards="" />
<action no="8" player="player5" type="4" sum="0" cards="" />
<action no="12" player="player5" type="3" sum="80" cards="" />
<action no="9" player="player6" type="5" sum="80" cards="" />
</round>
<round no="3">
<cards type="Turn" player="">H9</cards>
<action no="13" player="player4" type="4" sum="0" cards="" />
<action no="16" player="player4" type="3" sum="320" cards="" />
<action no="14" player="player5" type="4" sum="0" cards="" />
<action no="17" player="player5" type="3" sum="320" cards="" />
<action no="15" player="player6" type="5" sum="320" cards="" />
</round>
<round no="4">
<cards type="River" player="">HJ</cards>
<action no="18" player="player4" type="4" sum="0" cards="" />
<action no="21" player="player4" type="0" sum="0" cards="" />
<action no="19" player="player5" type="4" sum="0" cards="" />
<action no="22" player="player5" type="0" sum="0" cards="" />
<action no="20" player="player6" type="5" sum="1,280" cards="" />
</round>
</game>
例如，在轮次no = 2中，动作节点不是顺序的，动作7不是第一个孩子，第二个在那里。我希望它是第一个。因此，我的排序文档的轮次no = 2应该如下所示：
<round no="2">
<cards type="Flop" player="">H4 CQ C8</cards>
<action no="7" player="player4" type="4" sum="0" cards="" />
<action no="8" player="player5" type="4" sum="0" cards="" />
<action no="9" player="player6" type="5" sum="80" cards="" />
<action no="10" player="player1" type="0" sum="0" cards="" />
<action no="11" player="player4" type="3" sum="80" cards="" />
<action no="12" player="player5" type="3" sum="80" cards="" />
</round>
我如何使用LINQ或其他简单的方法来实现。注意在排序后只有动作节点会改变，其他节点将保持在同一个地方。
答案 0 :(得分：1)
这应该根据需要对xml的action部分进行排序。需要在Select()内删除以取消当前无序操作与父项的关联。完成后，我们重新添加有序操作。
static void Main()
{
var root = XElement.Parse(xmlToParse);
var orderedRoundElements= root.Elements("round")
.Select(element=>{
var actions = element.Elements("action")
.OrderBy(elem=> (int)elem.Attribute("no"))
.ToList();
actions.Remove();
element.Add(actions);
return element;
}).ToList();
Console.WriteLine(root.ToString());
}
答案 1 :(得分：0)
正如您所说，如果操作都在卡片后面进行分组，您不必介意，可以使用LINQ to XML解析它并删除所有操作元素，并按排序顺序添加它们：
var doc = XDocument.Parse(xml);
foreach (var round in doc.Descendants("round"))
{
var sortedActions = round.Elements("action")
.OrderBy(e => (int)e.Attribute("no"))
.ToList();
sortedActions.Remove();
round.Add(sortedActions);
}
如果你已经在你的代码中解析了XML，那么你可以在阅读每一轮时简单地对它们进行排序。