Question

这个程序运行得很好，但就像一个真正的赌场老板。我希望在不增加更多可能性的情况下尽可能减少支出。我想这样做的方法是为每个数字添加概率。有8种可能性（2,3,4,5,6,7,8,9）我希望7发生最少。因此，我希望将概率设置为2-6（75％）（每次15％）8-9（20％）（每次10％）和7％（5％）。有人能帮我吗？

#include <cstdlib>
#include <iostream>
#include <cmath>
#include <ctime>

using namespace std;
int Random(int low, int high);
int Result(int a, int b, int c, int chips, int bet);
int main()
{
  srand( time(0) );
  int low1(2), low2(2), low3(2);
  int high1(9), high2(9), high3(9);
  int menu=0;
  int bet =0;
  bool quit=0;
  cout << "Player's chips: $1000" << endl;
  int chips=1000;
  while (!quit)
  {
     cout << "1) Play slot. 2) Exit.";
     cin >> menu;
     switch (menu)
     {
        case 1:
        {
           cout << "Enter your bet: ";
           cin >> bet;
           if (bet<=0 || bet>chips)
           {
              cout << "You did not enter a valid bet." << endl;
              menu=1;
           }
           else
           {
              int a = Random(low1,high1);
              int b = Random(low2,high2);
              int c = Random(low3,high3);
              cout << a << " " << b << " " << c << endl;
              chips = Result(a,b,c,chips,bet);
              cout << "Player's chips: $" << Result(a,b,c,chips,bet) << endl;
           }
           break;
        }
        case 2:
        {
             cout << "Exiting..." << endl;
             quit=1;
             break;
        }
        default:
        {
        cout << "Not a valid menu !"<<endl;
        }
     }
   }
     if (chips <=0)
     {
         cout << "You have $0 ! Game Over !" << endl;
         quit=1;
     }
}

 int Random(int low, int high)
 {
    int random;
    random = low + rand() % ((high+1)-low);
    return random;
 }

  int Result(int a, int b, int c, int chips, int bet)
  {
     if ((a==7 && b==7 && c==7))
     {
       cout << "You won 10 times your bet !($" << (bet*10) << ")" << endl;
       chips=chips+(bet*10);
     }
     if ((a==b==c) && !(a==7 && b==7 && c==7))
     {
        cout << "You won 5 times your bet !($" << (bet*5) << ")" << endl;
        chips=chips+(bet*5);
     }
      if ((a==b || a==c || b==c) && !(a==b==c) && !(a==7 && b==7 && c==7))
     {
      chips=chips+(bet*3);
      cout << "You won 3 times your bet ! ($" << (bet*3) << ")" << endl;
      }
    else 
    {
      cout << "You lost your bet ! ($-" << bet << ")" << endl;
      chips=chips-bet;
    }
     return chips;
 }

Answer 1

引入对应于值7,8,9,2,3,4,5的值[0.05,0.15,0.25,0.4,0.55,0.7,0.85]的数组.6如果生成的随机数> 0.85。

然后从0到1得到一个随机数r。

if r <=0.05 then it is 7
else if r <= 0.15 then it is 8
else if r <= 0.1 then it is 9
...
else if r <= 0.85 then it is 5
else it is 6

如果需要，你可以弄清楚如何将其写成循环。

Answer 2

我会按如下方式重新编写函数（可以将其重新编写成更好的东西，但它应该起作用）：

// Generate a random number 2-9, with weighted probabilities
int Random()
{
   int number; // number 1-9 to generate
   int prob; // probability

   // Generate probability value 0-99
   prob = rand() % 100;

   // Calculate number with desired probability "additive"
   if (prob < 15) // 15% probability for 2
     number = 2;
   else if (prob < 30) // 15% probability for 3
     number = 3;
   else if (prob < 45) // 15% probability for 4
     number = 4;
   else if (prob < 60) // 15% probability for 5
     number = 5;
   else if (prob < 75) // 15% probability for 6
     number = 6;
   else if (prob < 80) // 5% probability for 7
     number = 7;
   else if (prob < 90) // 10% probability for 8
     number = 8;
   else                // 10% probability for 9
     number = 9;
   return number;
}

不要忘记添加以下代码来播种随机数生成器：

srand (time(NULL));

顺便提一下，我希望这不是一个真正的老虎机，如果是这样的话可能会出现法律问题： - ）

如何为游戏添加概率？

2 个答案: