图像处理Opencv

Question

我对opencv有疑问。我试图实现SURF算法。当我尝试构建代码但我收到以下错误。

*****error LNK2019: unresolved external symbol _cvExtractSURF referenced in function _main
1>SAMPLE.obj : error LNK2019: unresolved external symbol _cvSURFParams referenced in function _main*****

我已经浏览了本论坛中与我的主题相关的所有帖子，但无法解决我的代码问题。请帮我解决我的问题。

代码：

#include <stdio.h>
#include <opencv2/features2d/features2d.hpp>
#include <opencv2/highgui/highgui.hpp>
#include <opencv2/imgproc/imgproc_c.h>
#include <opencv2\objdetect\objdetect.hpp>
#include <opencv2\calib3d\calib3d.hpp>
#include <opencv2\core\core.hpp>
#include <opencv2\legacy\legacy.hpp>
#include <opencv2\legacy\compat.hpp>
#include <opencv2/nonfree/nonfree.hpp>
#include <opencv\opensurf\surf.h>
using namespace cv;
using namespace std;
int main(int argc, char** argv)
{
  CvMemStorage* storage = cvCreateMemStorage(0);
cvNamedWindow("Image", 1);
int key = 0;
static CvScalar red_color[] ={0,0,255};
IplImage* capture= cvLoadImage( "testface.jpg");

CvMat* prevgray = 0, *image = 0, *gray =0;
while( key != 'q' )
{
int firstFrame = gray == 0;
IplImage* frame =capture;
if(!frame)
break;
if(!gray)
{
image = cvCreateMat(frame->height, frame->width, CV_8UC1);
}

//Convert the RGB image obtained from camera into Grayscale
cvCvtColor(frame, image, CV_BGR2GRAY);

//Define sequence for storing surf keypoints and descriptors
CvSeq *imageKeypoints = 0, *imageDescriptors = 0;

int i;

//Extract SURF points by initializing parameters
CvSURFParams params = cvSURFParams(500,1);
cvExtractSURF( image, 0, &imageKeypoints, &imageDescriptors, storage, params );
printf("Image Descriptors: %d\n", imageDescriptors->total);

//draw the keypoints on the captured frame
for( i = 0; i < imageKeypoints->total; i++ )
{
CvSURFPoint* r = (CvSURFPoint*)cvGetSeqElem( imageKeypoints, i );
CvPoint center;
int radius;
center.x = cvRound(r->pt.x);
center.y = cvRound(r->pt.y);
radius = cvRound(r->size*1.2/9.*2);
cvCircle( frame, center, radius, red_color[0], 1, 8, 0 );
}
cvShowImage( "Image", frame );

cvWaitKey(0);
}
cvDestroyWindow("Image");
return 0
}

谢谢你，
Sreelakshmi Priya