当我尝试通过测试平台模拟以下模块时,我收到此错误:“未解析的引用'if2to4'”。
这是我的代码:
module h3to8(din, eout, en);
//Port Assignments
input [2:0] din;
input [0:0] en;
output reg [7:0] eout;
//3-to-8 decoder
always @(din)
begin
eout = 8'b00000000;
if(din[2] == 1'b0)
if2to4 half1 (din[1:0], eout[3:0], en);
else
if2to4 half2 (din[1:0], eout[7:4], en);
end
endmodule
module if2to4 (in, out, en);
//Port Assignments
input [1:0] in;
input [0:0] en;
output reg [3:0] out;
//2-to-4 decoder
always @(in)
begin
if(en == 0)
out = 4'b0000;
else
if(in == 0)
out = 1;
else if(in == 1)
out = 2;
else if(in == 2)
out = 4;
else
out = 8;
end
endmodule
verilog代码旨在使用两个2到4解码器实现3到8解码器。我以为我正确地实例化了模块,但是我一直收到关于模块if2to4
的未解决的引用错误。代码编译时没有错误,只有在尝试运行模拟时才会出现此特定错误。
感谢任何反馈。
答案 0 :(得分:2)
您不能像这样在always块中实例化模块。试试这个:
module h3to8(din, eout, en);
//Port Assignments
input [2:0] din;
input [0:0] en;
output reg [7:0] eout;
//3-to-8 decoder
if2to4 half1 (din[1:0], eout[3:0], en);
if2to4 half2 (din[1:0], eout[7:4], en);
endmodule
更新:
module h3to8(din, eout, en);
//Port Assignments
input [2:0] din;
input [0:0] en;
output reg [7:0] eout;
//3-to-8 decoder
if2to4 half1 (din[1:0], eout[3:0], en&~din[2]);
if2to4 half2 (din[1:0], eout[7:4], en&din[2]);
endmodule