Question

我试图重现不是“保存线程”字典的行为并实施样本（见下文）。我期待死锁，但测试没有任何问题。请帮助解释我的测试中的问题以及如何模拟多线程字典错误。

using System;
using System.Collections.Generic;
using System.Diagnostics;
using System.Threading;
using System.Threading.Tasks;
using Microsoft.VisualStudio.TestTools.UnitTesting;

namespace parallelTest
{
    [TestClass]
    public class UnitTest1
    {
        Dictionary<int, string> dictionary = new Dictionary<int, string>();
        [TestMethod]
        public void TestMethod1()
        {
            dictionary[2000] = "test";

            Parallel.For(0, 1000, i =>
            {
                string value;
                dictionary.TryGetValue(2000, out value);
                dictionary[2000] = String.Format("new value {0}", i);
                dictionary.Add(i, String.Format("{0}", i));
                Trace.WriteLine(String.Format("thread: {0}, {1}, {2}", Thread.CurrentThread.ManagedThreadId, i, value));
                Thread.Sleep(100);
            }
            );
        }
    }
}

Answer 1

您不能面临死锁，因为Dictionary未锁定其内部数据但是，您可能会在字典中找到意外数据。在这种情况下：未添加的项目。

您需要检查字典是否与压力测试后的预期相符。

for(Int32  index=0; index < 1000; index++)
{
    if(dictionary.Values.Any(index.ToString()) ==  false)
    {
          // problem
    }

}

顺便说一下，如果你想强调字典，你需要删除函数中的所有其他操作，例如的String.Format。通过这样做，您将增加在字典中创建问题的机会。

这是调用public add方法时调用的内部方法，正如您所看到的那样，没有锁定。

private void Insert(TKey key, TValue value, bool add)
{
    if (key == null)
    {
        ThrowHelper.ThrowArgumentNullException(ExceptionArgument.key);
    }
    if (this.buckets == null)
    {
        this.Initialize(0);
    }
    int num = this.comparer.GetHashCode(key) & 2147483647;
    int num2 = num % this.buckets.Length;
    int num3 = 0;
    for (int i = this.buckets[num2]; i >= 0; i = this.entries[i].next)
    {
        if (this.entries[i].hashCode == num && this.comparer.Equals( this.entries[i].key
                                                                   , key))
        {
            if (add)
            {
                ThrowHelper.ThrowArgumentException(ExceptionResource
                                                      .Argument_AddingDuplicate);
            }
            this.entries[i].value = value;
            this.version++;
            return;
        }
        num3++;
    }
    int num4;
    if (this.freeCount > 0)
    {
        num4 = this.freeList;
        this.freeList = this.entries[num4].next;
        this.freeCount--;
    }
    else
    {
        if (this.count == this.entries.Length)
        {
            this.Resize();
            num2 = num % this.buckets.Length;
        }
        num4 = this.count;
        this.count++;
    }
    this.entries[num4].hashCode = num;
    this.entries[num4].next = this.buckets[num2];
    this.entries[num4].key = key;
    this.entries[num4].value = value;
    this.buckets[num2] = num4;
    this.version++;
    if (num3 > 100 && HashHelpers.IsWellKnownEqualityComparer(this.comparer))
    {
        this.comparer = (IEqualityComparer<TKey>)HashHelpers
                                    .GetRandomizedEqualityComparer(this.comparer);
        this.Resize(this.entries.Length, true);
    }
}

我希望它有所帮助。

如何模拟不是“安全线程”字典的行为？

1 个答案: