Question

我正在读这个post关于获得2点之间的角度并且想知道。我认为atan2是为atan2（y，x）定义的，这里是atan2（deltaX，deltaY），为什么x现在是第一个？

public float getAngle(Point target) {
    float angle = (float) Math.toDegrees(Math.atan2(target.x - x, target.y - y));

    if (angle < 0) {
        angle += 360;
    }

    return angle;
}

Answer 1

Math.java定义为

 public static double atan2(double y, double x) {
    return StrictMath.atan2(y, x); // default impl. delegates to StrictMath
  }

这将返回相对于X轴的逆时针角度。

如果你互换那两个，你将获得相对于X轴的时钟角度。

在笛卡尔坐标系中，我们考虑相对于X轴的逆时针角度。这就是Math.java如上所述使用它的原因。

Answer 2

交换参数的顺序意味着不是与X轴的（逆时针）角度，而是获得与Y轴的（顺时针）角度。这没错，只是不寻常。

Answer 3

试试这个：

// ... code
Target start = new Target();
        start.setX(0);
        start.setY(0);
        Target aLine = new Target();
        Target bLine = new Target();
        aLine.setX(-65000);
        aLine.setY(ress.getObstacle().getLine());
        bLine.setX(65000);
        bLine.setY(ress.getObstacle().getLine());
        Line2D line = new Line2D.Float(aLine.getX(), aLine.getY(), bLine.getX(), bLine.getY());

        List<Target> list = new ArrayList<Target>();

        if (!(ress.getObstacle().getLine() == 0)) {
            //check if points are there , if yes just reinitialize a linea-lineb and calculate the same in for:

            String a = "";
            try {
                a = ress.getObstacle().getA().toStrin`enter code here`g();
            } catch (NullPointerException e) {

            }
            if (!(a == "")) {
                aLine.setX(ress.getObstacle().getA().getX());
                aLine.setY(ress.getObstacle().getLine());
                bLine.setX(ress.getObstacle().getB().getX());
                bLine.setY(ress.getObstacle().getLine());
                Line2D lineNew = new Line2D.Float(aLine.getX(), aLine.getY(), bLine.getX(), bLine.getY());

                for (Target t : ress.getTargets()) {
                    Line2D line2 = new Line2D.Float(start.getX(), start.getY(), t.getX(), t.getY());
                    if (!line2.intersectsLine(lineNew)) {
                        list.add(t);
                    }
                }
            } else {
        //-------------------start old part----------------------------------
                 for (Target t : ress.getTargets()) {
                       Line2D line2 = new Line2D.Float(start.getX(), start.getY(), t.getX(), t.getY());
                         if (!line2.intersectsLine(line)) {
                            list.add(t);
                         }
                 }
                 ///////-------end old part
            }

        } else {
            double angA = Math.toDegrees(StrictMath.atan2(ress.getObstacle().getA().getX() - start.getX(), ress.getObstacle().getA().getY() - start.getY()));
            double angB = Math.toDegrees(StrictMath.atan2(ress.getObstacle().getB().getX() - start.getX(), ress.getObstacle().getB().getY() - start.getY()));

            Boolean up = (ress.getObstacle().getA().getY()>0)&(ress.getObstacle().getB().getY()>0);
            Boolean left = (ress.getObstacle().getA().getX()<0)&(ress.getObstacle().getB().getX()<0);
            Boolean right = (ress.getObstacle().getA().getX()>0)&(ress.getObstacle().getB().getX()>0);

            for (Target t : ress.getTargets()) {
                double angT = Math.toDegrees(StrictMath.atan2(t.getX() - start.getX(), t.getY() - start.getY()));

                if (up) {

                    if (!((angT > Math.min(angA,angB)) & (angT < Math.max(angB,angA))))
                        list.add(t);
                } else
                    if (right || left) {
                    if ( !((angT > Math.min(angA,angB)) & (angT< Math.max(angB,angA)))) {
                       list.add(t);
                    }
                } else
                    {
                        if ( ((angT > Math.min(angA,angB)) & (angT< Math.max(angB,angA)))) {
                            list.add(t);
                        }
                    }
            }
        }


        sol.setTargets(list);

atan2与2点之间的角度

3 个答案: