线段之间交叉的麻烦

时间:2013-05-03 15:12:38

标签: java android math

我有一个路径存储为arraylist中的点,我想检查线段是否相交。由于某种未知的原因,它不起作用!尽管我正在绘制一个相交的形状,但我在LogCat中没有收到任何消息。如果有人能够看到我做错了什么或者有如何改进代码的建议,那就更准确了。

    // Intersection control
    if(touchActionUp) {

        // Loop throw all points except the last 3
        for (int i = 0; i < points.size()-3; i++) {
            Line line1 = new Line(points.get(i), points.get(i+1));

            // Begin after the line above and check all points after that
            for (int j = i + 2; j < points.size()-1; j++) {
                Line line2 = new Line(points.get(j), points.get(j+1));

                // Call method to check intersection
                if(checkIntersection(line1, line2)) {
                    Log.i("Intersection", "Yes!");
                }
            }
        }
    }

方法:

    // Method to check for intersection between lines
private boolean interceptionControl(Line line1, Line line2) {
    int x1 = line1.pointX1;
    int x2 = line1.pointX2;
    int x3 = line2.pointX1;
    int x4 = line2.pointX2;

    int y1 = line1.pointY1;
    int y2 = line1.pointY2;
    int y3 = line2.pointY1;
    int y4 = line2.pointY2;

    // Check if lines are parallel

    int denom = (y4 - y3) * (x2 - x1) - (x4 - x3) * (y2 - y1);

    if(denom == 0) { // Lines are parallel
        // ??
    }

    double a = ((x4 - x3) * (y1 - y3) - (y4 - y3) * (x1 - x3)) / denom;
    double b = ((x2 - x1) * (y1 - y3) - (y2 - y1) * (x1 - x3)) / denom;

    // Check for intersection
    if( a >= 0.0f && a <= 1.0f && b >= 0.0f && b <= 1.0f) {
        return true;
    }
    return false;
}

1 个答案:

答案 0 :(得分:0)

您使用int作为坐标,因此它进行整数除法(即3/2 = 1)。这可能是您除以denom的原因。您可以通过除以((double)denom)而不是简单地denom来修复它。