我正在为类似GTA2的游戏开发物理学,这样我就可以学到更多关于游戏物理的知识。
碰撞检测和解决方案运行良好。
我现在只是不确定当我撞墙时如何计算接触点。
这是我的OBB课程:
public class OBB2D
{
private Vector2D projVec = new Vector2D();
private static Vector2D projAVec = new Vector2D();
private static Vector2D projBVec = new Vector2D();
private static Vector2D tempNormal = new Vector2D();
private Vector2D deltaVec = new Vector2D();
// Corners of the box, where 0 is the lower left.
private Vector2D corner[] = new Vector2D[4];
private Vector2D center = new Vector2D();
private Vector2D extents = new Vector2D();
private RectF boundingRect = new RectF();
private float angle;
//Two edges of the box extended away from corner[0].
private Vector2D axis[] = new Vector2D[2];
private double origin[] = new double[2];
public OBB2D(float centerx, float centery, float w, float h, float angle)
{
for(int i = 0; i < corner.length; ++i)
{
corner[i] = new Vector2D();
}
for(int i = 0; i < axis.length; ++i)
{
axis[i] = new Vector2D();
}
set(centerx,centery,w,h,angle);
}
public OBB2D(float left, float top, float width, float height)
{
for(int i = 0; i < corner.length; ++i)
{
corner[i] = new Vector2D();
}
for(int i = 0; i < axis.length; ++i)
{
axis[i] = new Vector2D();
}
set(left + (width / 2), top + (height / 2),width,height,0.0f);
}
public void set(float centerx,float centery,float w, float h,float angle)
{
float vxx = (float)Math.cos(angle);
float vxy = (float)Math.sin(angle);
float vyx = (float)-Math.sin(angle);
float vyy = (float)Math.cos(angle);
vxx *= w / 2;
vxy *= (w / 2);
vyx *= (h / 2);
vyy *= (h / 2);
corner[0].x = centerx - vxx - vyx;
corner[0].y = centery - vxy - vyy;
corner[1].x = centerx + vxx - vyx;
corner[1].y = centery + vxy - vyy;
corner[2].x = centerx + vxx + vyx;
corner[2].y = centery + vxy + vyy;
corner[3].x = centerx - vxx + vyx;
corner[3].y = centery - vxy + vyy;
this.center.x = centerx;
this.center.y = centery;
this.angle = angle;
computeAxes();
extents.x = w / 2;
extents.y = h / 2;
computeBoundingRect();
}
//Updates the axes after the corners move. Assumes the
//corners actually form a rectangle.
private void computeAxes()
{
axis[0].x = corner[1].x - corner[0].x;
axis[0].y = corner[1].y - corner[0].y;
axis[1].x = corner[3].x - corner[0].x;
axis[1].y = corner[3].y - corner[0].y;
// Make the length of each axis 1/edge length so we know any
// dot product must be less than 1 to fall within the edge.
for (int a = 0; a < axis.length; ++a)
{
float l = axis[a].length();
float ll = l * l;
axis[a].x = axis[a].x / ll;
axis[a].y = axis[a].y / ll;
origin[a] = corner[0].dot(axis[a]);
}
}
public void computeBoundingRect()
{
boundingRect.left = JMath.min(JMath.min(corner[0].x, corner[3].x), JMath.min(corner[1].x, corner[2].x));
boundingRect.top = JMath.min(JMath.min(corner[0].y, corner[1].y),JMath.min(corner[2].y, corner[3].y));
boundingRect.right = JMath.max(JMath.max(corner[1].x, corner[2].x), JMath.max(corner[0].x, corner[3].x));
boundingRect.bottom = JMath.max(JMath.max(corner[2].y, corner[3].y),JMath.max(corner[0].y, corner[1].y));
}
public void set(RectF rect)
{
set(rect.centerX(),rect.centerY(),rect.width(),rect.height(),0.0f);
}
// Returns true if other overlaps one dimension of this.
private boolean overlaps1Way(OBB2D other)
{
for (int a = 0; a < axis.length; ++a) {
double t = other.corner[0].dot(axis[a]);
// Find the extent of box 2 on axis a
double tMin = t;
double tMax = t;
for (int c = 1; c < corner.length; ++c) {
t = other.corner[c].dot(axis[a]);
if (t < tMin) {
tMin = t;
} else if (t > tMax) {
tMax = t;
}
}
// We have to subtract off the origin
// See if [tMin, tMax] intersects [0, 1]
if ((tMin > 1 + origin[a]) || (tMax < origin[a])) {
// There was no intersection along this dimension;
// the boxes cannot possibly overlap.
return false;
}
}
// There was no dimension along which there is no intersection.
// Therefore the boxes overlap.
return true;
}
public void moveTo(float centerx, float centery)
{
float cx,cy;
cx = center.x;
cy = center.y;
deltaVec.x = centerx - cx;
deltaVec.y = centery - cy;
for (int c = 0; c < 4; ++c)
{
corner[c].x += deltaVec.x;
corner[c].y += deltaVec.y;
}
boundingRect.left += deltaVec.x;
boundingRect.top += deltaVec.y;
boundingRect.right += deltaVec.x;
boundingRect.bottom += deltaVec.y;
this.center.x = centerx;
this.center.y = centery;
computeAxes();
}
// Returns true if the intersection of the boxes is non-empty.
public boolean overlaps(OBB2D other)
{
if(right() < other.left())
{
return false;
}
if(bottom() < other.top())
{
return false;
}
if(left() > other.right())
{
return false;
}
if(top() > other.bottom())
{
return false;
}
if(other.getAngle() == 0.0f && getAngle() == 0.0f)
{
return true;
}
return overlaps1Way(other) && other.overlaps1Way(this);
}
public Vector2D getCenter()
{
return center;
}
public float getWidth()
{
return extents.x * 2;
}
public float getHeight()
{
return extents.y * 2;
}
public void setAngle(float angle)
{
set(center.x,center.y,getWidth(),getHeight(),angle);
}
public float getAngle()
{
return angle;
}
public void setSize(float w,float h)
{
set(center.x,center.y,w,h,angle);
}
public float left()
{
return boundingRect.left;
}
public float right()
{
return boundingRect.right;
}
public float bottom()
{
return boundingRect.bottom;
}
public float top()
{
return boundingRect.top;
}
public RectF getBoundingRect()
{
return boundingRect;
}
public boolean overlaps(float left, float top, float right, float bottom)
{
if(right() < left)
{
return false;
}
if(bottom() < top)
{
return false;
}
if(left() > right)
{
return false;
}
if(top() > bottom)
{
return false;
}
return true;
}
public static float distance(float ax, float ay,float bx, float by)
{
if (ax < bx)
return bx - ay;
else
return ax - by;
}
public Vector2D project(float ax, float ay)
{
projVec.x = Float.MAX_VALUE;
projVec.y = Float.MIN_VALUE;
for (int i = 0; i < corner.length; ++i)
{
float dot = Vector2D.dot(corner[i].x,corner[i].y,ax,ay);
projVec.x = JMath.min(dot, projVec.x);
projVec.y = JMath.max(dot, projVec.y);
}
return projVec;
}
public Vector2D getCorner(int c)
{
return corner[c];
}
public int getNumCorners()
{
return corner.length;
}
public static float collisionResponse(OBB2D a, OBB2D b, Vector2D outNormal)
{
float depth = Float.MAX_VALUE;
for (int i = 0; i < a.getNumCorners() + b.getNumCorners(); ++i)
{
Vector2D edgeA;
Vector2D edgeB;
if(i >= a.getNumCorners())
{
edgeA = b.getCorner((i + b.getNumCorners() - 1) % b.getNumCorners());
edgeB = b.getCorner(i % b.getNumCorners());
}
else
{
edgeA = a.getCorner((i + a.getNumCorners() - 1) % a.getNumCorners());
edgeB = a.getCorner(i % a.getNumCorners());
}
tempNormal.x = edgeB.x -edgeA.x;
tempNormal.y = edgeB.y - edgeA.y;
tempNormal.normalize();
projAVec.equals(a.project(tempNormal.x,tempNormal.y));
projBVec.equals(b.project(tempNormal.x,tempNormal.y));
float distance = OBB2D.distance(projAVec.x, projAVec.y,projBVec.x,projBVec.y);
if (distance > 0.0f)
{
return 0.0f;
}
else
{
float d = Math.abs(distance);
if (d < depth)
{
depth = d;
outNormal.equals(tempNormal);
}
}
}
float dx,dy;
dx = b.getCenter().x - a.getCenter().x;
dy = b.getCenter().y - a.getCenter().y;
float dot = Vector2D.dot(dx,dy,outNormal.x,outNormal.y);
if(dot > 0)
{
outNormal.x = -outNormal.x;
outNormal.y = -outNormal.y;
}
return depth;
}
public Vector2D getMoveDeltaVec()
{
return deltaVec;
}
};
答案 0 :(得分:4)
我现在只是不确定当我点击时如何计算接触点 壁。
您可以用简单的平面表示墙。
OBB-vs-plane交叉点测试是其中最简单的separating axis test
:
如果两个凸面物体不相交,那么就有一个平面在哪里 这两个物体的投影不会相交。
仅当平面法线形成分离轴时,框才与平面相交。计算盒子中心的投影和投影半径(4个点积和几个加法)你很好(你也可以获得穿透深度for free
)。
条件如下:
| d | &lt; = a1 | n * A1 | + a2 | n * A2 | + a3 | n * A3 |
下面:
从箱子中心到飞机的距离 d
。
a1...a3
来自中心的框的范围。
n
飞机法线
A1...A3
方框的x,y,z轴
某些伪代码:
//Test if OBB b intersects plane p
int TestOBBPlane(OBB b, Plane p)
{
// Compute the projection interval radius of b onto L(t) = b.c + t * p.n
float r = b.e[0]*Abs(Dot(p.n, b.u[0])) +
b.e[1]*Abs(Dot(p.n, b.u[1])) +
b.e[2]*Abs(Dot(p.n, b.u[2]));
// Compute distance of box center from plane
float s = Dot(p.n, b.c) – p.d;
// Intersection occurs when distance s falls within [-r,+r] interval
return Abs(s) <= r;
}
OBB-vs-OBB交叉点测试更复杂。
让我们参考this great tutorial:
在这种情况下,我们不再有相应的分离线 垂直于分离轴。相反,我们分开了 分隔边界体积的平面(它们是垂直的 到它们相应的分离轴)。
在3D空间中,每个OBB只有3个由其面扩展的独特平面, 分离平面与这些面平行。我们是 对平行于面的分离平面感兴趣,但是在3D中 空间,面孔不是唯一的问题。我们也感兴趣 边缘。感兴趣的分离平面平行于面 的盒子和感兴趣的分离轴垂直于 分离面。因此,感兴趣的分离轴是 垂直于每个盒子的3个独特面孔。请注意这些6 分离感兴趣的轴对应于6个局部(XYZ)轴 这两个盒子。
所以有9个分离轴要考虑边缘碰撞 除了6个分离轴,我们已经找到了面孔 碰撞。这使得可能的分离轴的总数达到 考虑在15岁。
以下是您需要测试的15种可能的分离轴(L):
CASE 1: L = Ax
CASE 2: L = Ay
CASE 3: L = Az
CASE 4: L = Bx
CASE 5: L = By
CASE 6: L = Bz
CASE 7: L = Ax x Bx
CASE 8: L = Ax x By
CASE 9: L = Ax x Bz
CASE 10: L = Ay x Bx
CASE 11: L = Ay x By
CASE 12: L = Ay x Bz
CASE 13: L = Az x Bx
CASE 14: L = Az x By
CASE 15: L = Az x Bz
下面:
Ax
单位向量表示A的x轴
Ay
单位向量表示A的y轴
Az
单位向量表示A的z轴
Bx
单位向量表示B的x轴
By
单位向量表示B的y轴
Bz
单位向量表示B的z轴
现在您可以看到OBB-OBB交叉测试背后的算法。
让我们跳转到源代码:
2D OBB-OBB:http://www.flipcode.com/archives/2D_OBB_Intersection.shtml
3D OBB-OBB:http://www.geometrictools.com/LibMathematics/Intersection/Intersection.html
P.S:此链接http://www.realtimerendering.com/intersections.html对那些希望超越飞机和盒子的人有用。