Question

我需要Number实例的二进制表示。首先，我使用参数toString()尝试了Number类的2方法。结果是14位。（对于数字9878.658456）然后，我尝试将Number实例添加到ByteArray中，如下所示：

    var b:ByteArray = new ByteArray();
    var n :Number = 9878.658456;
    trace(uint(n).toString(2));
    b.writeDouble(n);

然后我尝试读取8个字节：

    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));
    trace((b.readByte() ).toString(2));

结果非常有趣，有二进制值，我不知道该怎么做。我觉得我还没理解toString方法，API解释对我来说还不够。有关检索Number实例的IEEE表示的任何帮助吗？

Answer 1

最佳解决方案是您自己的解决方案。我想出了这个：

    var b:ByteArray = new ByteArray();
    var n :Number = 9878.658456;
    b.writeDouble(n);
    b.position=0;
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));
    trace((b.readByte() & 0xFF).toString(2));

您可以检查here的结果，效果很好。

IEEE双精度格式中Number的二进制表示

1 个答案: