Question

我在每日时间记录中对数据进行分组和排序时遇到问题自动生成报告。 DTR的表结构如下：

LogDate     LogTime     EmployeeName            LogType
2012-09-14  10:48:04    SALITA, LYNYRD ANTONIO  LOGOUT
2012-09-14  09:39:29    SALITA, LYNYRD ANTONIO  LOGOUT
2012-09-14  09:39:19    SALITA, LYNYRD ANTONIO  LOGIN
2012-09-14  09:35:25    SALITA, LYNYRD ANTONIO  LOGOUT
2012-09-14  09:35:13    SALITA, LYNYRD ANTONIO  LOGIN
2012-09-14  08:10:00    SALITA, LYNYRD ANTONIO  LOGIN
2012-09-13  17:00:00    SALITA, LYNYRD ANTONIO  LOGOUT
2012-09-13  08:05:00    SALITA, LYNYRD ANTONIO  LOGIN
2012-09-12  17:05:00    SALITA, LYNYRD ANTONIO  LOGOUT
2012-09-12  08:05:00    SALITA, LYNYRD ANTONIO  LOGIN
2012-07-10  17:00:00    MAG-ISA, MAYBELLE       LOGOUT
2012-07-10  17:00:00    BELO, RIO               LOGOUT
2012-07-10  17:00:00    CANSINO, PAUL           LOGOUT
2012-07-10  17:00:00    SALITA, LYNYRD ANTONIO  LOGOUT
2012-07-10  17:00:00    AURENO, LEAH            LOGOUT
2012-07-10  17:00:00    GARCIA, ALVIN           LOGOUT
2012-07-10  17:00:00    TARINE, KAREN           LOGOUT
2012-07-10  17:00:00    REYES, ANDREA           LOGOUT
2012-07-10  17:00:00    NAVARRO, KRISTINA       LOGOUT
2012-07-10  10:30:00    MAG-ISA, MAYBELLE       LOGIN
2012-07-10  08:00:00    SALITA, LYNYRD ANTONIO  LOGIN
2012-07-10  08:00:00    CANSINO, PAUL           LOGIN
2012-07-10  08:00:00    BELO, RIO               LOGIN
2012-07-10  07:40:00    AURENO, LEAH            LOGIN
2012-07-10  07:30:00    GARCIA, ALVIN           LOGIN
2012-07-10  07:25:00    TARINE, KAREN           LOGIN
2012-07-10  07:10:00    NAVARRO, KRISTINA       LOGIN
2012-07-10  07:10:00    REYES, ANDREA           LOGIN

用这个sql：

SELECT 
    DATE_FORMAT(LogDate, '%d/%c/%Y') AS LogDate, 
    EmployeeName,
    (GROUP_Concat(CASE LogType WHEN 'LOGIN' THEN LogTime END)) AS LOGIN,
    (GROUP_Concat(CASE LogType WHEN 'LOGOUT' THEN LogTime END)) AS LOGOUT
FROM myTable
GROUP BY LogDate, EmployeeName
ORDER BY LogDate desc;

我能够产生这个结果

LogDate     EmployeeName            Login                       Logout
2012-09-14  SALITA, LYNYRD ANTONIO  08:10:00,09:35:13,09:39:19  09:35:25,09:39:29,10:48:04
2012-09-13  SALITA, LYNYRD ANTONIO  08:05:00                    17:00:00
2012-09-12  SALITA, LYNYRD ANTONIO  08:05:00                    17:05:00
2012-07-10  REYES, ANDREA           07:10:00                    17:00:00
2012-07-10  NAVARRO, KRISTINA       07:10:00                    17:00:00
2012-07-10  TARINE, KAREN           07:25:00                    17:00:00
2012-07-10  GARCIA, ALVIN           07:30:00                    17:00:00
2012-07-10  AURENO, LEAH            07:40:00                    17:00:00
2012-07-10  CANSINO, PAUL           08:00:00                    17:00:00
2012-07-10  SALITA, LYNYRD ANTONIO  08:00:00                    17:00:00
2012-07-10  BELO, RIO               08:00:00                    17:00:00
2012-07-10  MAG-ISA, MAYBELLE       10:30:00                    17:00:00

根据其中一个答案，这是代码：

SELECT DATE_FORMAT(t1.LogDate, '%d/%c/%Y') AS LogDate, t1.EmployeeName
     , t1.LogTime AS Login
     , ( SELECT MIN(t2.LogTime) FROM myTable t2
          WHERE t2.LogType = 'LOGOUT'
            AND t2.LogDate = t1.LogDate
            AND t2.EmployeeName = t1.EmployeeName
            AND t2.LogTime > t1.LogTime ) AS Logout
  FROM myTable t1
 WHERE t1.LogType = 'LOGIN'

它产生了这个结果：

LogDate     EmployeeName            Login       Logout
2012-09-14  SALITA, LYNYRD ANTONIO  08:10:00    09:35:25
2012-09-14  SALITA, LYNYRD ANTONIO  09:35:13    09:35:25
2012-09-14  SALITA, LYNYRD ANTONIO  09:39:19    09:39:29
2012-09-13  SALITA, LYNYRD ANTONIO  08:05:00    17:00:00
2012-09-12  SALITA, LYNYRD ANTONIO  08:05:00    17:05:00
2012-07-10  REYES, ANDREA           07:10:00    17:00:00
2012-07-10  NAVARRO, KRISTINA       07:10:00    17:00:00
2012-07-10  TARINE, KAREN           07:25:00    17:00:00
2012-07-10  GARCIA, ALVIN           07:30:00    17:00:00
2012-07-10  AURENO, LEAH            07:40:00    17:00:00
2012-07-10  CANSINO, PAUL           08:00:00    17:00:00
2012-07-10  SALITA, LYNYRD ANTONIO  08:00:00    17:00:00
2012-07-10  BELO, RIO               08:00:00    17:00:00
2012-07-10  MAG-ISA, MAYBELLE       10:30:00    17:00:00

有没有办法让结果像这样排序？

LogDate     EmployeeName            Login       Logout
2012-09-14  SALITA, LYNYRD ANTONIO  08:10:00    NULL
2012-09-14  SALITA, LYNYRD ANTONIO  09:35:13    09:35:25
2012-09-14  SALITA, LYNYRD ANTONIO  09:39:19    09:39:29
2012-09-14  SALITA, LYNYRD ANTONIO  NULL        10:48:04
2012-09-13  SALITA, LYNYRD ANTONIO  08:05:00    17:00:00
2012-09-12  SALITA, LYNYRD ANTONIO  08:05:00    17:05:00
2012-07-10  REYES, ANDREA           07:10:00    17:00:00
2012-07-10  NAVARRO, KRISTINA       07:10:00    17:00:00
2012-07-10  TARINE, KAREN           07:25:00    17:00:00
2012-07-10  GARCIA, ALVIN           07:30:00    17:00:00
2012-07-10  AURENO, LEAH            07:40:00    17:00:00
2012-07-10  CANSINO, PAUL           08:00:00    17:00:00
2012-07-10  SALITA, LYNYRD ANTONIO  08:00:00    17:00:00
2012-07-10  BELO, RIO               08:00:00    17:00:00
2012-07-10  MAG-ISA, MAYBELLE       10:30:00    17:00:00

Answer 1

这样的事情：

SELECT DATE_FORMAT(t1.LogDate, '%d/%c/%Y') AS LogDate, t1.EmployeeName
     , t1.LogTime AS Login
     , ( SELECT MIN(t2.LogTime) FROM myTable t2
          WHERE t2.LogType = 'LOGOUT'
            AND t2.LogDate = t1.LogDate
            AND t2.EmployeeName = t1.EmployeeName
            AND t2.LogTime > t1.LogTime ) AS Logout
  FROM myTable t1
 WHERE t1.LogType = 'LOGIN'

没有GROUP BY是必要的，因为你实际上并没有对任何东西进行分组。

复杂的sql分组和排序

1 个答案: