See this SQLFiddle

Question

我在每日时间记录中对数据进行分组和排序时遇到问题自动生成报告。 DTR的表结构如下：

Log Date    Log Time    Employee Name           Log Type
9/13/2012   17:00:00    SALITA, LYNYRD ANTONIO  LOGOUT
9/13/2012   8:05:00     SALITA, LYNYRD ANTONIO  LOGIN
9/12/2012   17:05:00    SALITA, LYNYRD ANTONIO  LOGOUT
9/12/2012   8:05:00     SALITA, LYNYRD ANTONIO  LOGIN
7/10/2012   17:00:00    GARCIA, ALVIN           LOGOUT
7/10/2012   17:00:00    AURENO, LEAH            LOGOUT
7/10/2012   17:00:00    SALITA, LYNYRD ANTONIO  LOGOUT
7/10/2012   17:00:00    CANSINO, PAUL           LOGOUT
7/10/2012   17:00:00    BELO, RIO               LOGOUT
7/10/2012   17:00:00    MAG-ISA, MAYBELLE       LOGOUT
7/10/2012   17:00:00    TARINE, KAREN           LOGOUT
7/10/2012   17:00:00    REYES, ANDREA           LOGOUT
7/10/2012   17:00:00    NAVARRO, KRISTINA       LOGOUT
7/10/2012   10:30:00    MAG-ISA, MAYBELLE       LOGIN
7/10/2012   8:00:00     SALITA, LYNYRD ANTONIO  LOGIN
7/10/2012   8:00:00     CANSINO, PAUL           LOGIN
7/10/2012   8:00:00     BELO, RIO               LOGIN
7/10/2012   7:40:00     AURENO, LEAH            LOGIN
7/10/2012   7:30:00     GARCIA, ALVIN           LOGIN
7/10/2012   7:25:00     TARINE, KAREN           LOGIN
7/10/2012   7:10:00     NAVARRO, KRISTINA       LOGIN
7/10/2012   7:10:00     REYES, ANDREA           LOGIN

我希望将它作为查询处理，输出如下：

Log Date    Employee Name           LOGIN       LOGOUT
9/13/2012   SALITA, LYNYRD ANTONIO  8:05:00     17:00:00
9/12/2012   SALITA, LYNYRD ANTONIO  8:05:00     17:05:00
7/10/2012   GARCIA, ALVIN           7:30:00     17:00:00
7/10/2012   AURENO, LEAH            7:40:00     17:00:00
7/10/2012   SALITA, LYNYRD ANTONIO  8:00:00     17:00:00
7/10/2012   CANSINO, PAUL           8:00:00     17:00:00
7/10/2012   BELO, RIO               8:00:00     17:00:00
7/10/2012   MAG-ISA, MAYBELLE       10:30:00    17:00:00
7/10/2012   TARINE, KAREN           7:25:00     17:00:00
7/10/2012   REYES, ANDREA           7:10:00     17:00:00
7/10/2012   NAVARRO, KRISTINA       7:10:00     17:00:00

我如何实现这一目标？

Answer 1

这是你想要得到的：

SELECT DATE_FORMAT(LogDate, '%d/%c/%Y') AS LogDate, EmployeeName,
   (GROUP_Concat(CASE LogType WHEN 'LOGIN' THEN LogTime END)) AS LOGIN,
   (GROUP_Concat(CASE LogType WHEN 'LOGOUT' THEN LogTime END)) AS LOGOUT
FROM myTable
GROUP BY LogDate, EmployeeName
ORDER BY LogDate desc;

See this SQLFiddle

查询说明：

使用CASE语句将行转换为列（Login和Logout）

SELECT DATE_FORMAT(LogDate, '%d/%c/%Y') AS LogDate, EmployeeName,
   (CASE LogType WHEN 'LOGIN' THEN LogTime END) AS LOGIN,
   (CASE LogType WHEN 'LOGOUT' THEN LogTime END) AS LOGOUT
FROM myTable
GROUP BY LogDate, EmployeeName, LogTime
ORDER BY LogDate desc;

但这会让你感觉像in this SQLFiddle.

因此，您需要使用GROUP_CONCAT（MySQL）与LogTime加入NULL，并从LogTime子句中删除GROUP BY。

Answer 2

Select  Log Date,   Employee Name,       LOGIN       LOGOUT 
    case(Log Type)
    when 'LOGIN' then Log Time AS LOGIN
    Else 
    Log Time AS LOGOUT
    End
From
YOUR_TABLE
order by Log Date desc

复杂的SQL排序和分组

2 个答案:

See this SQLFiddle