我有一个困难的访问问题,我似乎被困在了。我的数据如下表所示,每个人都有一个开始和结束日期以及两者之间的天数。我想要做的是将所有连续的分配长度加在一起,这意味着一个的结束日期是下一个的开始日期的前一天。在下面的例子中,我想总结记录1,2,3的分配长度和单独的总和4,5,因为在结束日期和开始日期之间有一个中断。它可以访问,所以我可以通过查询或使用vba进行访问,我不确定这里的最佳解决方案是什么。
ID名称StartDate EndDate AssignmentLength
1 - bob - 1/1/2013 - 2/1/2013 - 30
2 - bob - 2/2/2013 - 3/1/2013 - 30
3 - bob - 3/2/2013 - 4/1/2013 - 30
4 - bob - 5/1/2013 - 6/1/2013 - 30
5 - bob - 6/2/2013 - 7/1/2013 - 30
答案 0 :(得分:2)
我在给定数据中添加了一条额外的记录:
periodID fname startdate enddate
6 bob 8/1/2013 9/1/2013
有一个期间没有跨越记录。我将表命名为workperiods。
通过修改后的数据,我们可以找到工作期间开始于:
SELECT *
FROM workperiods
WHERE periodid NOT IN
(SELECT a.periodid
FROM workperiods a
INNER JOIN workperiods b ON a.startdate =b.enddate+1);
我们可以找到工作期结束
SELECT *
FROM workperiods
WHERE periodid NOT IN
( SELECT a.periodid
FROM workperiods a
INNER JOIN workperiods b ON a.enddate =b.startdate-1);
然后我们可以建立这种怪异:
SELECT startdate,
enddate,
enddate-startdate AS periodlength
FROM
(SELECT startdate,
min(enddate) AS enddate
FROM
(SELECT c.startdate,
f.enddate
FROM
(SELECT *
FROM workperiods
WHERE periodid NOT IN
(SELECT a.periodid
FROM workperiods a
INNER JOIN workperiods b ON a.startdate =b.enddate+1)) AS c,
(SELECT *
FROM workperiods
WHERE periodid NOT IN
(SELECT d.periodid
FROM workperiods d
INNER JOIN workperiods e ON d.enddate =e.startdate-1)) AS f
WHERE f.startdate >c.enddate
OR c.startdate=f.startdate)
GROUP BY startdate)
给出了:
startdate enddate periodlength
1/1/2013 4/1/2013 90
5/1/2013 7/1/2013 61
8/1/2013 9/1/2013 31
这可能是期望的结果。
它不漂亮,但我认为它到了那里。
答案 1 :(得分:1)
我会使用VBA和DateDiff()。然后你可以循环遍历每个并比较以查看总数是否小于1.
答案 2 :(得分:1)
也许你可以从中得到一些想法。 AssignmentLength可以根据月份的实际长度进行修改。如果您有任何想法,请标记为已回答。
Sub dates()
Dim cn As ADODB.Connection
Dim rs As ADODB.Recordset
Dim ConnStr As String
''Dim below arrays
Set cn = New ADODB.Connection
ConnStr = "Provider=Microsoft.Jet.OLEDB.4.0;Data Source=" & _
"C:\Users\Philosophaie\Documents\a access\a Chase.mdb;"
cn.Open ConnStr
Set rs = New ADODB.Recordset
rs.Open Source:="Checking", ActiveConnection:=cn, _
CursorType:=adOpenKeyset, LockType:=adLockOptimistic, _
Options:=adCmdTableDirect
rs.MoveFirst
Do Until rs.EOF
If rs!Name = "bob" Then
n=n+1
datestart(n)=rs!StartDate
dateend(n)=rs!EndDate
assignmentlength(n)=rs!AssignmentLength
End If
rs.MoveNext
Loop
for i=1 to n
mostart(i)=Left(datestart(i),1)
dystart(i)=right(left(datestart,3),1)
yrstart(i)=right(datestart,4)
''do the same for end
next I
for i=1 to n
if moend(I)=mostart(i) then
if dyend(I)=daystart(I)+1 then
if yrend(I)=yrstart(I) then
aslen(j)=assignmentlength(I)+aslen(j)
else
j=j+1
end if
else
j=j+1
end if
else
j=j+1
end if
next I
''output
End sub