Python多处理.Pool在Windows上很奇怪

时间:2012-07-16 17:08:07

标签: python windows multiprocessing pool

我有一个如此定义的超级简单的python脚本

import multiprocessing
from multiprocessing import Pool

print "CPUs: " + str(multiprocessing.cpu_count())
convertPool = Pool(multiprocessing.cpu_count())

在Linux上,这看起来像我预期的那样,程序刚启动,然后打印出核心数,然后退出。但是,在Windows上,这个程序将继续调用新的python命令并打印出“CPU:4”(我有4个核心)并且永远不会停止运行并最终会杀死该框。有人可以解释一下这里发生了什么吗?

由于

编辑: 我现在有以下程序仍然没有按照我的预期运作

import sys
import os
import subprocess
from subprocess import Popen, PIPE
from threading import Thread
import multiprocessing
from multiprocessing import Pool, freeze_support

try:
    from Queue import Queue, Empty
except ImportError:
    from queue import Queue, Empty  # python 3.x

ON_POSIX = "posix" in sys.builtin_module_names

def myPrint(line, logWriter):
    if logWriter is None:
        # This will print without a newline, cause the process
        # has its own newlines
        sys.stdout.write(line)
    else:
        logWriter.write(line.strip())
        logWriter.write("\n")
        logWriter.flush()

# This is gotten from http://stackoverflow.com/questions/375427/non-blocking-read-on-a-subprocess-pipe-in-python
def executeCommand(cmd, logWriter):
   myPrint(cmd + "\n", logWriter)
    p = Popen(cmd, stdout=PIPE, bufsize=4096, close_fds=ON_POSIX, shell=True)
    q = Queue()
    t = Thread(target=enqueue_output, args=(p.stdout, q))
    t.daemon = True # thread dies with the program
    t.start()

    # read line without blocking
    while t.isAlive() or not q.empty():
        try:
            line = q.get_nowait() # or q.get(timeout=.1)
        except Empty:
            pass # Do nothing
        else: # If there is a line, then print it 
            if logWriter is not None:
                myPrint(line, logWriter)
        # Sleep to prevent python from using too much cpu
        time.sleep(0.05)

if __name__ == "__main__":
    freeze_support()
    convertPool = Pool(multiprocessing.cpu_count())
    # Now let's smooth and threshold all the masks
    for foo in bar:
        threshSmoothCmd = "ConvertImage.exe -i " + foo + " -o " + foo
        myPrint(threshSmoothCmd + "\n", None)
        convertPool.apply_async(executeCommand,(threshSmoothCmd, None,))

    convertPool.close()
    convertPool.join()
print "Finished processing"

ConvertImage.exe是我自己编写的可执行文件foo和bar只是占位符。在Linux上,这将激活multiprocessing.cpu_count()的ConvertImage.exe进程数,然后在所有ConvertImage.exe进程完成后打印完成处理。在Windows上,这会立即激活len(bar)ConvertImage.exe进程,然后立即打印完成处理并退出。如何使Windows版本的行为与Linux版本相同?

1 个答案:

答案 0 :(得分:0)

我想通了,它工作正常,我的示例程序发布错误,因为我忘记了一些导入,导致了所描述的行为。在我完成所有导入后,这个例子在Windows和Linux上运行良好。