我遇到了跨产品功能的问题。我需要为每个像素取两个向量的叉积,然后求和所有像素的结果。
i=1;
[h,w,d] = size(current_vec);
for pxRow = 1:h % fixed pixel row
for pxCol = 1:w % fixed pixel column
for pxsize = 1:d
for r = 1:h % row of distant pixel
for c = 1:w % column of distant pixel
for dpth = 1:d
bfield(c,r,dpth) = cross(current_vec(c,r,dpth),dist_vec(c,r,dpth)); % pythagoras theorem to get distance to each pixel % unit vector from x to s
end
end
end
Bfield(i) = {bfield}; % filling a cell array with results. read below
i = i+1;
end
end
end
??? Error using ==> cross at 37
A and B must have at least one dimension of length 3.
??? Error using ==> cross at 37
A and B must have at least one dimension of length 3.
Error in ==> MAC2 at 71
bfield(c,r,dpth) = cross(current_vec(c,r,dpth),dist_vec(c,r,dpth));
但是有问题的向量current_vec和dist_vec如下:
>> size(current_vec)
ans =
35 35 3
>> size(dist_vec)
ans =
35 35 3
因此,就我而言,他们填写了在交叉产品中使用的标准。为什么不是这种情况?
答案 0 :(得分:3)
您需要使用cross
的矢量化形式:
bfield = cross(current_vec,dist_vec);
cross
将在长度为3的第一个维度上工作。使用嵌套循环执行此操作的方式,您通过索引访问单个元素(标量)。你不能用标量穿过标量。