Question

数据：
这是样本表（TableA）数据

ID  StartTime               EndTime
1   2012-03-22 06:00:00.000     2012-03-22 06:30:00.000
2   2012-03-22 06:15:00.000     2012-03-22 06:45:00.000
3   2012-03-22 06:30:00.000     2012-03-22 07:00:00.000
4   2012-03-22 06:45:00.000     2012-03-22 07:15:00.000
5   2012-03-22 07:00:00.000     2012-03-22 07:30:00.000
6   2012-03-22 07:15:00.000     2012-03-22 07:45:00.000
8   2012-03-22 07:30:00.000     2012-03-22 08:00:00.000
9   2012-03-22 07:45:00.000     2012-03-22 08:15:00.000
10  2012-03-22 08:00:00.000     2012-03-22 08:30:00.000
11  2012-03-22 08:15:00.000     2012-03-22 08:45:00.000
12  2012-03-22 08:30:00.000     2012-03-22 09:00:00.000
13  2012-03-22 08:45:00.000     2012-03-22 09:15:00.000
14  2012-03-22 09:00:00.000     2012-03-22 09:30:00.000
15  2012-03-22 09:15:00.000     2012-03-22 09:45:00.000
16  2012-03-22 09:30:00.000     2012-03-22 10:00:00.000

要求：
获取给定时间范围的连续时间集。例如时间范围：06：00至08:00

预期产出：

ID  StartTime               EndTime
1   2012-03-22 06:00:00.000     2012-03-22 06:30:00.000
3   2012-03-22 06:30:00.000     2012-03-22 07:00:00.000
5   2012-03-22 07:00:00.000     2012-03-22 07:30:00.000
8   2012-03-22 07:30:00.000     2012-03-22 08:00:00.000

问题：
是否可以使用sql查询获得预期的输出？我不想使用循环。

我想出了这个，但它只过滤了第一个非连续的行。

SELECT *
 FROM TableA TableA_OUTER (nolock) 
WHERE CONVERT(VARCHAR(5),EndTime,114) <= CONVERT(VARCHAR(5),CAST('08:00' AS DATETIME),114)
AND (CONVERT(VARCHAR(5),StartTime,114) = CONVERT(VARCHAR(5),CAST('06:00' AS DATETIME),114) OR EXISTS 
(SELECT NULL from TableA TableA_INNER (nolock) 
where  CONVERT(VARCHAR(5),TableA_OUTER.StartTime,114) = CONVERT(VARCHAR(5),TableA_INNER.EndTime,114)
))

真的很感谢你的帮助！

Answer 1

试试这个

-- Create table

CREATE TABLE [dbo].[TableA](
    [ID] [int] NULL,
    [StartTime] [datetime] NULL,
    [EndTime] [datetime] NULL
) ON [PRIMARY]

GO

--insert sample data
Insert Into TableA (ID,StartTime,EndTime) values(1   ,'2012-03-22 06:00:00.000',     '2012-03-22 06:30:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(2   ,'2012-03-22 06:15:00.000',     '2012-03-22 06:45:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(3   ,'2012-03-22 06:30:00.000',     '2012-03-22 07:00:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(4   ,'2012-03-22 06:45:00.000',     '2012-03-22 07:15:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(5   ,'2012-03-22 07:00:00.000',     '2012-03-22 07:30:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(6   ,'2012-03-22 07:15:00.000',     '2012-03-22 07:45:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(8   ,'2012-03-22 07:30:00.000',     '2012-03-22 08:00:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(9   ,'2012-03-22 07:45:00.000',     '2012-03-22 08:15:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(10  ,'2012-03-22 08:00:00.000',     '2012-03-22 08:30:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(11  ,'2012-03-22 08:15:00.000',     '2012-03-22 08:45:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(12  ,'2012-03-22 08:30:00.000',     '2012-03-22 09:00:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(13  ,'2012-03-22 08:45:00.000',     '2012-03-22 09:15:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(14  ,'2012-03-22 09:00:00.000',     '2012-03-22 09:30:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(15  ,'2012-03-22 09:15:00.000',     '2012-03-22 09:45:00.000' )
Insert Into TableA (ID,StartTime,EndTime) values(16  ,'2012-03-22 09:30:00.000',     '2012-03-22 10:00:00.000' )

 --query

Declare @AnchorElement int
Set @AnchorElement = (Select top 1 ID  from TableA 
where '2012-03-22 06:00:00.000' 
between StartTime and EndTime
Order by StartTime
)
;


 With ListStartingAtDate (ID,  StartTime, EndTime ,Level ) as
    (
        -- Anchor Timeframe definition
        select ID,  StartTime, EndTime , 0 as Level From TableA 
            --Where ID = @AnchorElement
            -- StartTime has to be matched exactly
            WHERE StartTime = '2012-03-22 06:00:00.000' 
        UNION ALL 
        -- Recursive Timeframe definition
        select a.ID,  a.StartTime, a.EndTime ,  Level +1 
        From TableA a
        INNER JOIN ListStartingAtDate b
        ON a.StartTime = b.EndTime

    )

    select  * from ListStartingAtDate
    where StartTime >= '2012-03-22 06:00:00.000' and EndTime <= '2012-03-22 08:00:00.000'

用于选择连续时间集的SQL查询

1 个答案: