Question

我有一个名为weight的表，字段为ID，WEIGHT，CREATED ON。我在PHP变量中也有START个日期和END日期。现在我希望从开始日期到结束日期获得一周的明智记录结果应该是这样的：

WEEK | WEIGHT | CREATED ON
-----+--------+-----------
1    |   50   | 2012-02-01
1    |   50   | 2012-02-03
1    |   50   | 2012-02-05
1    |   50   | 2012-02-07
2    |   50   | 2012-02-08
2    |   50   | 2012-02-10
2    |   50   | 2012-02-14
3    |   50   | 2012-02-15
3    |   50   | 2012-02-17
3    |   50   | 2012-02-17

如何实现它？

Answer 1

希望有所帮助

SELECT ID, weigth, created_on, WEEK(created_on) week
FROM weight
WHERE created_on BETWEEN start_date AND end_date
ORDER BY week

Answer 2

如果已经在PHP变量中存储了开始日期和结束日期，则可以使用MySQL BETWEEN关键字对表执行SELECT查询，因此（PHP代码）：

$query = "SELECT FROM weight WHERE `created on` BETWEEN '" . $start_date . "' AND '" . $end_date . "'";

我在上面包含了字符串引号（'），因为我假设您已将变量存储为格式化为日期时间的PHP字符串，即YYYY-MM-DD HH：MM：SS，使用{{1}格式：date()。

进一步阅读：http://dev.mysql.com/doc/refman/5.0/en/comparison-operators.html#operator_between

Answer 3

尝试这个...

SELECT WEEKDAY(CREATED_ON)AS weekdays,weight,CREATED_ON
FROM weight
WHERE CREATED_on BETWEEN start_date AND end_date
GROUP BY weekdays

Answer 4

尝试以下

SELECT WEEKDAY(CREATED_ON) AS week, weight, created_on
FROM weight
WHERE CREATED_on BETWEEN start_date AND end_date
ORDER BY week

这可以给你你想要的......

更新1

SELECT (SELECT COUNT(*) FROM myTable u2 
WHERE 
u2.date > u1.date) + 1 AS week, date FROM myTable u1
WHERE date between start_date AND end_date
ORDER BY week

更新2

在下面的查询中，日期是我的日期。

SELECT  (WEEK(date, 5) -
    WEEK(DATE_SUB(date, INTERVAL DAYOFMONTH(date) - 1 DAY), 5) + 1) as week, date
FROM myTable
WHERE date BETWEEN start_date AND end_date
ORDER BY week

更新3

假设我有

myDate
+++++++++++++++++++++
2012-02-01 12:12:12
2012-02-01 12:12:12
2012-02-01 12:12:12
2012-02-03 12:12:12
2012-02-05 12:12:12
2012-02-07 12:12:12
2012-02-08 12:12:12
2012-02-08 12:12:12
2012-02-10 12:12:12
2012-02-14 12:12:12
2012-02-15 12:12:12
2012-02-17 12:12:12
2012-02-17 12:12:12
2012-03-01 12:12:12
2012-03-03 12:12:12
2012-03-05 12:12:12
2012-03-07 12:12:12

以下是我想要的。

week |myDate
+++++++++++++++++++++++++++
  1  |2012-03-07 12:12:12
  2  |2012-03-05 12:12:12
  3  |2012-03-03 12:12:12
  4  |2012-03-01 12:12:12
  5  |2012-02-17 12:12:12
  5  |2012-02-17 12:12:12
  6  |2012-02-15 12:12:12
  7  |2012-02-14 12:12:12
  8  |2012-02-10 12:12:12
  9  |2012-02-08 12:12:12
  9  |2012-02-08 12:12:12
  10 |2012-02-07 12:12:12
  11 |2012-02-05 12:12:12
  12 |2012-02-03 12:12:12
  13 |2012-02-01 12:12:12
  13 |2012-02-01 12:12:12
  13 |2012-02-01 12:12:12

要获得更多信息，请参阅以下查询...

SELECT (SELECT COUNT(distinct u2.myDate) FROM myTable u2
WHERE 
u2.myDate > u1.myDate) + 1 AS week, myDate FROM myTable u1
WHERE 1=1
ordeR BY week

在您的情况下，WHERE子句将为WHERE myDate between startDate AND endDate

希望这是你想要的......终于!!!

祝你好运!!!

Answer 5

计算START日期和CREATED ON日期之间的差异（全天），除以7，然后加1 - 如下所示：

SELECT
  DATEDIFF(CREATED_ON, START) / 7 + 1,
  WEIGHT,
  CREATED_ON
FROM
  weight
ORDER BY
  CREATED_ON

如何从开始到结束日期在mysql中获得周智能记录

5 个答案:

更新1

更新2

更新3

希望这是你想要的......终于!!!

祝你好运!!!