获取当前周的开始日期和结束日期(星期一从星期一开始,到星期日结束)

时间:2011-12-05 05:42:28

标签: javascript date

我想显示当前周的开始日期和结束日期。 (周开始=周一,周末=周日) 我设法显示星期一。

但是我无法得到星期天的约会。 如果有人有解决方案,请发帖给我。

13 个答案:

答案 0 :(得分:31)

<script>
Date.prototype.getWeek = function(start)
{
        //Calcing the starting point
    start = start || 0;
    var today = new Date(this.setHours(0, 0, 0, 0));
    var day = today.getDay() - start;
    var date = today.getDate() - day;

        // Grabbing Start/End Dates
    var StartDate = new Date(today.setDate(date));
    var EndDate = new Date(today.setDate(date + 6));
    return [StartDate, EndDate];
}

// test code
var Dates = new Date().getWeek();
alert(Dates[0].toLocaleDateString() + ' to '+ Dates[1].toLocaleDateString())
</script>

我相信这有效。

答案 1 :(得分:11)

以下功能可以解决问题:

// return an array of date objects for start (monday)
// and end (sunday) of week based on supplied 
// date object or current date
function startAndEndOfWeek(date) {

  // If no date object supplied, use current date
  // Copy date so don't modify supplied date
  var now = date? new Date(date) : new Date();

  // set time to some convenient value
  now.setHours(0,0,0,0);

  // Get the previous Monday
  var monday = new Date(now);
  monday.setDate(monday.getDate() - monday.getDay() + 1);

  // Get next Sunday
  var sunday = new Date(now);
  sunday.setDate(sunday.getDate() - sunday.getDay() + 7);

  // Return array of date objects
  return [monday, sunday];
}

// Mon Nov 12 2012 00:00:00
// Sun Nov 18 2012 00:00:00
alert(startAndEndOfWeek(new Date(2012,10,14)).join('\n'));

答案 2 :(得分:10)

试试这个:

var current = new Date();     // get current date    
var weekstart = current.getDate() - current.getDay() +1;    
var weekend = weekstart + 6;       // end day is the first day + 6 
var monday = new Date(current.setDate(weekstart));  
var sunday = new Date(current.setDate(weekend));

答案 3 :(得分:3)

SetDate将设置该月的某一天。在月初和月末使用setDate将导致错误的一周

var curr = new Date("08-Jul-2014"); // get current date
var first = curr.getDate() - curr.getDay(); // First day is the day of the month - the day of the week
var last = first + 6; // last day is the first day + 6
var firstday = new Date(curr.setDate(first)); // 06-Jul-2014
var lastday = new Date(curr.setDate(last)); // 12-Jul-2014

如果设置日期为2014年7月1日,则将显示第一天为2014年6月29日,最后一天为2014年6月5日,而不是2014年7月5日。所以为了解决这个问题,我用了

var curr = new Date();
day = curr.getDay();
firstday = new Date(curr.getTime() - 60*60*24* day*1000); // will return firstday (i.e. Sunday) of the week
lastday = new Date(curr.getTime() + 60 * 60 *24 * 6 * 1000); // adding (60*60*6*24*1000) means adding six days to the firstday which results in lastday (Saturday) of the week

答案 4 :(得分:2)

在其他例子中,当星期天在其他月份下降时,你会遇到问题。 这应该可以解决问题:

var today, todayNumber, mondayNumber, sundayNumber, monday, sunday;
    today = new Date();
    todayNumber = today.getDay();
    mondayNumber = 1 - todayNumber;
    sundayNumber = 7 - todayNumber;
    monday = new Date(today.getFullYear(), today.getMonth(), today.getDate()+mondayNumber);
    sunday = new Date(today.getFullYear(), today.getMonth(), today.getDate()+sundayNumber);

答案 5 :(得分:1)

根据RobG的回答,我最终得到这个星期一,从星期一午夜开始,星期日23:59:59.999结束。

  var weekMap = [6, 0, 1, 2, 3, 4, 5];

  function startAndEndOfWeek(date) {
    var now = new Date(date);
    now.setHours(0, 0, 0, 0);
    var monday = new Date(now);
    monday.setDate(monday.getDate() - weekMap[monday.getDay()]);
    var sunday = new Date(now);
    sunday.setDate(sunday.getDate() - weekMap[sunday.getDay()] + 6);
    sunday.setHours(23, 59, 59, 999);
    return [monday, sunday];
  }

答案 6 :(得分:1)

@ReadWriteCode的略微修改答案,这也适用于不同月份。

Date.prototype.getWeek = function()
{
    var today = new Date();
    var day = today.getDay();
    var date = today.getDate() - day;

        // Grabbing Start/End Dates
    var StartDate = new Date();
    var EndDate = new Date();
    StartDate.setHours(0,0,0,0); EndDate.setHours(0,0,0,0);
    StartDate.setDate(today.getDate()-day);
    EndDate.setDate(today.getDate()-day+6);
    return {
        startDate:StartDate,
        endDate: EndDate
    };
} 
var thisWeekDates=new Date().getWeek();

答案 7 :(得分:0)

您可以修改返回值以满足您的需求,现在它只返回星期日的完整对象。

Date.prototype.endWeek=function(){
  return new Date(this.getFullYear(), this.getMonth(),(7-this.getDay())+this.getDate());
}

//call like this
var myDate = new Date(); 
var Sunday = myDate.endWeek();
alert("Sunday falls on "+ Sunday.getDate());

答案 8 :(得分:0)

我希望这对你有用:

Date.prototype.getWeekEndDate = function () {
    diff = 6 - this.getDay();
    if (diff < 0) {
        diff += 6;
    }
    this.setDate(this.getDate() + (1 * diff));
    return this;
}
Date.prototype.getWeekStartDate = function () {
    diff = this.getDay() - 6;
    if (diff < 0) {
        diff += 7;
    }
    return this.setDate(this.getDate() + (-1 * diff));
}

这些方法将返回一周的开始日期和结束日期。

答案 9 :(得分:0)

  1. 以下代码也修复了不同月份的问题。
  2. 添加了格式“M.dd.yyyy”功能。

    function startAndEndOfWeek(setDate) {     var day = null; var date = null; var month = null; var year = null;     var mon = null; var tue = null; var wed = null; var thu = null; var fri = null; var sat = null; var sun = null;

    var now = setDate ? new Date(setDate) : new Date();
    now.setHours(0,0,0,0);
    
    var monday = new Date(now); var tuesday = new Date(now); var wednesday = new Date(now); var thursday = new Date(now);
    var friday = new Date(now); var saturday = new Date(now); var sunday = new Date(now); 
    
    if(new Date(now).getDay() == 0)
    {
        monday.setDate(monday.getDate() - 6);
        tuesday.setDate(tuesday.getDate() - 5);
        wednesday.setDate(wednesday.getDate() - 4);
        thursday.setDate(thursday.getDate() - 3);
        friday.setDate(friday.getDate() - 2);
        saturday.setDate(saturday.getDate() - 1);
        sunday.setDate(sunday.getDate() - 0);
    }
    else
    {
        monday.setDate(monday.getDate() - monday.getDay() + 1);
        tuesday.setDate(tuesday.getDate() - tuesday.getDay() + 2);
        wednesday.setDate(wednesday.getDate() - wednesday.getDay() + 3);
        thursday.setDate(thursday.getDate() - thursday.getDay() + 4);
        friday.setDate(friday.getDate() - friday.getDay() + 5);
        saturday.setDate(saturday.getDate() - saturday.getDay() + 6);
        sunday.setDate(sunday.getDate() - sunday.getDay() + 7);
    }
    
    date = monday.getDate();
    month = monday.getMonth();
    year = monday.getFullYear();
    mon = getMonthValue(month) + "." + getDateValue(date) + "." +  year;
    
    date = tuesday.getDate();
    month = tuesday.getMonth();
    year = tuesday.getFullYear();
    tue = getMonthValue(month) + "." + getDateValue(date) + "." +  year;
    
    date = wednesday.getDate();
    month = wednesday.getMonth();
    year = wednesday.getFullYear();
    wed = getMonthValue(month) + "." + getDateValue(date) + "." +  year;
    
    date = thursday.getDate();
    month = thursday.getMonth();
    year = thursday.getFullYear();
    thu = getMonthValue(month) + "." + getDateValue(date) + "." +  year;
    
    date = friday.getDate();
    month = friday.getMonth();
    year = friday.getFullYear();
    fri = getMonthValue(month) + "." + getDateValue(date) + "." +  year;
    
    date = saturday.getDate();
    month = saturday.getMonth();
    year = saturday.getFullYear();
    sat = getMonthValue(month) + "." + getDateValue(date) + "." +  year;
    
    date = sunday.getDate();
    month = sunday.getMonth();
    year = sunday.getFullYear();
    sun = getMonthValue(month) + "." + getDateValue(date) + "." +  year;
    
    return [mon, tue , wed, thu, fri, sat, sun];
    

    }

    function getMonthValue(month) {     开关(月)     {         案例0:返回“Jan”;                 打破;         案例1:返回“2月”;                 打破;         案例2:返回“Mar”;                 打破;         案例3:返回“4月”;                 打破;         案例4:返回“五月”;                 打破;         案例5:返回“君”;                 打破;         案例6:返回“Jul”;                 打破;         案例7:返回“8月”;                 打破;         案例8:返回“九月”;                 打破;         案例9:返回“十月”;                 打破;         案例10:返回“11月”;                 打破;         案例11:返回“Dec”;                 打破;     } } function getDateValue(day) {     if(parseInt(day)&lt; 10)     {         返回“0”+天;     }     返回日; }

答案 10 :(得分:0)

使用https://momentjs.com使其更简单。

  1. 要获取周从周日开始到周六, 然后使用:moment()。startOf(“ week”)。toDate()和 moment()。endOf(“ week”)。toDate()

  2. 要获取一周从星期一开始到星期日结束, 然后使用:moment()。startOf(“ isoWeek”)。toDate()和moment()。endOf(“ isoWeek”)。toDate()

在v2.18.1时刻进行了尝试,可以正常工作。

希望这会有所帮助,有关更多信息,您可以参考一下相关文档。

答案 11 :(得分:0)

this link

nginx.ingress.kubernetes.io/rewrite-target: /$2

答案 12 :(得分:0)

纯香草JS。没有第三方库。周日至周日上午 00 点返回。

const now = new Date()
const startOfWeek = new Date(now.getFullYear(), now.getMonth(), now.getDate() - now.getDay())
const endOfWeek = new Date(now.getFullYear(), now.getMonth(), startOfWeek.getDate() + 7)