function getStartAndEndOfWeek(date) {
var curr = date ? new Date(date) : new Date();
var first = curr.getDate() - curr.getDay();
var firstday = new Date(curr.setDate(first));
var lastday = new Date(curr.setDate(firstday.getDate() + 6));
return [firstday, lastday];
}
我无法将周开始设为周一。上面的代码将第一天作为星期日。此外,如果我们添加第一加一,它将给星期一作为开始,但问题是在哪里可以说(06/29/2014,星期日)是输入,它应该返回(06/23/2014作为开始和06 / 29/2014)结束。我们怎样才能做到这一点?如果我添加"第一个+ 1"它将06/30/2014作为开始日期和2014年6月7日作为结束日期返回。有帮助吗?感谢。
答案:
function getStartAndEndOfWeek(date) {
//Calculating the starting point
var curr = date ? new Date(date) : new Date();
var first = curr.getDate() - dayOfWeek(curr);
var firstday, lastday;
if (first < 1) {
//Get prev month and year
var k = new Date(curr.valueOf());
k.setDate(1);
k.setMonth(k.getMonth() - 1);
var prevMonthDays = new Date(k.getFullYear(), (k.getMonth() + 1), 0).getDate();
first = prevMonthDays - (dayOfWeek(curr) - curr.getDate());
firstday = new Date(k.setDate(first));
lastday = new Date(k.setDate(first + 6));
} else {
// First day is the day of the month - the day of the week
firstday = new Date(curr.setDate(first));
lastday = new Date(curr.setDate(first + 6));
}
return [firstday, lastday];
}
function dayOfWeek(date, firstDay) {
var daysOfWeek = {
sunday: 0,
monday: 1,
tuesday: 2,
wednesday: 3,
thursday: 4,
friday: 5,
saturday: 6,
};
firstDay = firstDay || "monday";
var day = date.getDay() - daysOfWeek[firstDay];
return (day < 0 ? day + 7 : day);
}
答案 0 :(得分:4)
如何制作一个简单的方法让您轻松操控一周的第一天:
(function() {
var original = Date.prototype.getDay;
var daysOfWeek = {
sunday: 0,
monday: 1,
tuesday: 2,
wednesday: 3,
thursday: 4,
friday: 5,
saturday: 6,
};
Date.prototype.getDay = function(weekBegins) {
weekBegins = (weekBegins || "sunday").toLowerCase();
return (original.apply(this) + 7 - daysOfWeek[weekBegins]) % 7;
};
})();
然后你可以简单地使用:
var first = curr.getDate() - curr.getDay("monday"),
last = first + 6;
答案 1 :(得分:2)
您可以先调整getDay()的结果,然后取结果的模数,先设置为星期一。
var first = curr.getDate() - ((curr.getDay() + 6) % 7);