我想获得当前周的开始和结束日期,我也想使用之前的日期 周开始和结束日期以及当月的开始和结束日期的下周。
先谢谢。
答案 0 :(得分:63)
rangeOfUnit:startDate:interval:forDate:
。它为您提供特定时间单位的开始和间隔。有了它,很容易在使用的日历中找到一周的开始,并添加范围-1以获得该周的最新秒。
NSCalendar *cal = [NSCalendar currentCalendar];
NSDate *now = [NSDate date];
NSDate *startOfTheWeek;
NSDate *endOfWeek;
NSTimeInterval interval;
[cal rangeOfUnit:NSWeekCalendarUnit
startDate:&startOfTheWeek
interval:&interval
forDate:now];
//startOfWeek holds now the first day of the week, according to locale (monday vs. sunday)
endOfWeek = [startOfTheWeek dateByAddingTimeInterval:interval-1];
// holds 23:59:59 of last day in week.
答案 1 :(得分:19)
感谢支持
,我解决了这个问题代码: - 它给出了当前的开始和结束日期。
NSDate *today = [NSDate date];
NSLog(@"Today date is %@",today);
dateFormat = [[NSDateFormatter alloc] init];
[dateFormat setDateFormat:@"yyyy-MM-dd"];// you can use your format.
//Week Start Date
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *components = [gregorian components:NSWeekdayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
int dayofweek = [[[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:today] weekday];// this will give you current day of week
[components setDay:([components day] - ((dayofweek) - 2))];// for beginning of the week.
NSDate *beginningOfWeek = [gregorian dateFromComponents:components];
NSDateFormatter *dateFormat_first = [[NSDateFormatter alloc] init];
[dateFormat_first setDateFormat:@"yyyy-MM-dd"];
dateString2Prev = [dateFormat stringFromDate:beginningOfWeek];
weekstartPrev = [[dateFormat_first dateFromString:dateString2Prev] retain];
NSLog(@"%@",weekstartPrev);
//Week End Date
NSCalendar *gregorianEnd = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *componentsEnd = [gregorianEnd components:NSWeekdayCalendarUnit | NSYearCalendarUnit | NSMonthCalendarUnit | NSDayCalendarUnit fromDate:today];
int Enddayofweek = [[[NSCalendar currentCalendar] components:NSWeekdayCalendarUnit fromDate:today] weekday];// this will give you current day of week
[componentsEnd setDay:([componentsEnd day]+(7-Enddayofweek)+1)];// for end day of the week
NSDate *EndOfWeek = [gregorianEnd dateFromComponents:componentsEnd];
NSDateFormatter *dateFormat_End = [[NSDateFormatter alloc] init];
[dateFormat_End setDateFormat:@"yyyy-MM-dd"];
dateEndPrev = [dateFormat stringFromDate:EndOfWeek];
weekEndPrev = [[dateFormat_End dateFromString:dateEndPrev] retain];
NSLog(@"%@",weekEndPrev);
答案 2 :(得分:12)
这是Swift 3版本: -
extension Date {
var startOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 1, to: sunday)
}
var endOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 7, to: sunday)
}
}
您可以像这样获得周开始日期和结束日期:
let startWeek = Date().startOfWeek
let endWeek = Date().endOfWeek
print(startWeek ?? "not found start date")
print(endWeek ?? "not found end date")
答案 3 :(得分:10)
vikingosegundo
answer的:
let calendar = NSCalendar.currentCalendar()
var startOfTheWeek: NSDate?
var endOfWeek: NSDate!
var interval = NSTimeInterval(0)
calendar.rangeOfUnit(.WeekOfMonth, startDate: &startOfTheWeek, interval: &interval, forDate: NSDate())
endOfWeek = startOfTheWeek!.dateByAddingTimeInterval(interval - 1)
答案 4 :(得分:8)
这是Swift 3(Xcode 8 +)的优雅方式:
extension Date {
var startOfWeek: Date {
let date = Calendar.current.date(from: Calendar.current.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self))!
let dslTimeOffset = NSTimeZone.local.daylightSavingTimeOffset(for: date)
return date.addingTimeInterval(dslTimeOffset)
}
var endOfWeek: Date {
return Calendar.current.date(byAdding: .second, value: 604799, to: self.startOfWeek)!
}
}
我们可以像这样使用这个扩展名:
print(Date().startOfWeek)
print(Date().endOfWeek)
答案 5 :(得分:4)
首先找到当前日期...
NSDate *today = [NSDate date];
NSCalendar *gregorian = [[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar];
NSDateComponents *weekdayComponents = [gregorian components:NSWeekdayCalendarUnit | NSHourCalendarUnit | NSMinuteCalendarUnit | NSSecondCalendarUnit fromDate:today];
计算从今天开始减去的天数,以便获得一周的第一天。在这种情况下,一周的第一天是星期一。这表示为首先用工作日整数减去0,然后将2添加到setDay。
星期日= 1,星期一= 2,星期二= 3,星期三= 4,星期四= 5,星期五= 6,星期六= 7.通过在此整数中添加更多,您将进入下周。
NSDateComponents *componentsToSubtract = [[NSDateComponents alloc] init];
[componentsToSubtract setDay: (0 - [weekdayComponents weekday]) + 2];
[componentsToSubtract setHour: 0 - [weekdayComponents hour]];
[componentsToSubtract setMinute: 0 - [weekdayComponents minute]];
[componentsToSubtract setSecond: 0 - [weekdayComponents second]];
创建第一天的日期
NSDate *beginningOfWeek = [gregorian dateByAddingComponents:componentsToSubtract toDate:today options:0];
在第一天的日期加上6,我们可以在星期日的例子中得到最后一天。
NSDateComponents *componentsToAdd = [gregorian components:NSDayCalendarUnit fromDate:beginningOfWeek];
[componentsToAdd setDay:6];
NSDate *endOfWeek = [gregorian dateByAddingComponents:componentsToAdd toDate:beginningOfWeek options:0];
为下一个和上一个....
-(IBAction)Week_CalendarActionEvents:(id)sender{
NSCalendar *gregorian = [[[NSCalendar alloc] initWithCalendarIdentifier:NSGregorianCalendar] autorelease];
NSDateComponents *offsetComponents = [[[NSDateComponents alloc] init] autorelease];
NSDate *nextDate;
if(sender==Week_prevBarBtn) // Previous button events
[offsetComponents setDay:-7];
else if(sender==Week_nextBarBtn) // next button events
[offsetComponents setDay:7];
nextDate = [gregorian dateByAddingComponents:offsetComponents toDate:selectedDate options:0];
selectedDate = nextDate;
[selectedDate retain];
NSDateComponents *components = [gregorian components:NSWeekCalendarUnit fromDate:selectedDate];
NSInteger week = [components week];
NSDateFormatter *formatter = [[NSDateFormatter alloc] init];
[formatter setDateFormat:@"MMMM YYYY"];
NSString *stringFromDate = [formatter stringFromDate:selectedDate];
[formatter release];
[Week_weekBarBtn setTitle:[NSString stringWithFormat:@"%@,Week %d",stringFromDate,week]];
}
答案 6 :(得分:2)
//Begining of Week Date
- (NSDate*) beginingOfWeekOfDate{
NSCalendar *tmpCalendar = [NSCalendar currentCalendar];
NSDateComponents *components = [tmpCalendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitWeekOfYear|NSCalendarUnitWeekday fromDate:self];//get the required calendar units
NSInteger weekday = tmpCalendar.firstWeekday;
components.weekday = weekday; //weekday
components.hour = 0;
components.minute = 0;
components.second = 0;
NSDate *fireDate = [tmpCalendar dateFromComponents:components];
return fireDate;
}
//End of Week Date
-(NSDate *)endOfWeekFromDate{
NSCalendar *tmpCalendar = [NSCalendar currentCalendar];
NSDateComponents *components = [tmpCalendar components:NSCalendarUnitYear|NSCalendarUnitMonth|NSCalendarUnitWeekOfYear|NSCalendarUnitWeekday fromDate:self];//get the required calendar units
int weekday = 7; //Saturday
if (tmpCalendar.firstWeekday != 1) {
weekday = 1;
}
components.weekday = weekday;//weekday
components.hour = 23;
components.minute = 59;
components.second = 59;
NSDate *fireDate = [tmpCalendar dateFromComponents:components];
return fireDate;
}
答案 7 :(得分:2)
这里有一些代码,它还会检查上周开始的前一个月的边缘情况。您可以将setWeekday
设置为7
来结束周末,并且可以通过从1
[components week]
来获得前一周的结果
// Finds the date for the first day of the week
- (NSDate *)getFirstDayOfTheWeekFromDate:(NSDate *)givenDate
{
NSCalendar *calendar = [NSCalendar currentCalendar];
// Edge case where beginning of week starts in the prior month
NSDateComponents *edgeCase = [[NSDateComponents alloc] init];
[edgeCase setMonth:2];
[edgeCase setDay:1];
[edgeCase setYear:2013];
NSDate *edgeCaseDate = [calendar dateFromComponents:edgeCase];
NSDateComponents *components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:edgeCaseDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(@"Edge case date is %@ and beginning of that week is %@", edgeCaseDate , [calendar dateFromComponents:components]);
// Find Sunday for the given date
components = [calendar components:NSYearCalendarUnit|NSMonthCalendarUnit|NSWeekCalendarUnit|NSWeekdayCalendarUnit fromDate:givenDate];
[components setWeekday:1]; // 1 == Sunday, 7 == Saturday
[components setWeek:[components week]];
NSLog(@"Original date is %@ and beginning of week is %@", givenDate , [calendar dateFromComponents:components]);
return [calendar dateFromComponents:components];
}
答案 8 :(得分:2)
这是swift4的解决方案, 我们可以获得本周的所有日子。
var calendar = Calendar(identifier: Calendar.Identifier.gregorian)
let today = calendar.startOfDay(for: Date())
let dayOfWeek = calendar.component(.weekday, from: today) - calendar.firstWeekday
let weekdays = calendar.range(of: .weekday, in: .weekOfYear, for: today)!
let days = (weekdays.lowerBound ..< weekdays.upperBound)
.flatMap { calendar.date(byAdding: .day, value: $0 - dayOfWeek, to: today) }
答案 9 :(得分:2)
Swift 4解决方案
我已经根据自己的要求弄清楚了,在那里我找到了后续的日期。
1. Today
2. Tomorrow
3. This Week
4. This Weekend
5. Next Week
6. Next Weekend
因此,我创建了Date Extension
来获取当前周和下周的日期。
代码
extension Date {
func getWeekDates() -> (thisWeek:[Date],nextWeek:[Date]) {
var tuple: (thisWeek:[Date],nextWeek:[Date])
var arrThisWeek: [Date] = []
for i in 0..<7 {
arrThisWeek.append(Calendar.current.date(byAdding: .day, value: i, to: startOfWeek)!)
}
var arrNextWeek: [Date] = []
for i in 1...7 {
arrNextWeek.append(Calendar.current.date(byAdding: .day, value: i, to: arrThisWeek.last!)!)
}
tuple = (thisWeek: arrThisWeek,nextWeek: arrNextWeek)
return tuple
}
var tomorrow: Date {
return Calendar.current.date(byAdding: .day, value: 1, to: noon)!
}
var noon: Date {
return Calendar.current.date(bySettingHour: 12, minute: 0, second: 0, of: self)!
}
var startOfWeek: Date {
let gregorian = Calendar(identifier: .gregorian)
let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self))
return gregorian.date(byAdding: .day, value: 1, to: sunday!)!
}
func toDate(format: String) -> String {
let formatter = DateFormatter()
formatter.dateFormat = format
return formatter.string(from: self)
}
}
用法:
let arrWeekDates = Date().getWeekDates() // Get dates of Current and Next week.
let dateFormat = "MMM dd" // Date format
let thisMon = arrWeekDates.thisWeek.first!.toDate(format: dateFormat)
let thisSat = arrWeekDates.thisWeek[arrWeekDates.thisWeek.count - 2].toDate(format: dateFormat)
let thisSun = arrWeekDates.thisWeek[arrWeekDates.thisWeek.count - 1].toDate(format: dateFormat)
let nextMon = arrWeekDates.nextWeek.first!.toDate(format: dateFormat)
let nextSat = arrWeekDates.nextWeek[arrWeekDates.nextWeek.count - 2].toDate(format: dateFormat)
let nextSun = arrWeekDates.nextWeek[arrWeekDates.nextWeek.count - 1].toDate(format: dateFormat)
print("Today: \(Date().toDate(format: dateFormat))") // Sep 26
print("Tomorrow: \(Date().tomorrow.toDate(format: dateFormat))") // Sep 27
print("This Week: \(thisMon) - \(thisSun)") // Sep 24 - Sep 30
print("This Weekend: \(thisSat) - \(thisSun)") // Sep 29 - Sep 30
print("Next Week: \(nextMon) - \(nextSun)") // Oct 01 - Oct 07
print("Next Weekend: \(nextSat) - \(nextSun)") // Oct 06 - Oct 07
您可以根据需要修改Extension
。
谢谢!
答案 10 :(得分:1)
利用rangeOfUnit:startDate:interval:forDate:
的{{1}}方法,有一种更简单的方法可以实现这一目标:
NSDate
所以现在你有了本周的开始日期和结束日期。然后上周:
- (void)startDate:(NSDate **)start andEndDate:(NSDate **)end ofWeekOn:(NSDate *)date{
NSDate *startDate = nil;
NSTimeInterval duration = 0;
BOOL b = [[NSCalendar currentCalendar] rangeOfUnit:NSWeekCalendarUnit startDate:&startDate interval:&duration forDate:date];
if(! b){
*start = nil;
*end = nil;
return;
}
NSDate *endDate = [startDate dateByAddingTimeInterval:duration-1];
*start = startDate;
*end = endDate;
}
NSDate *this_start = nil, *this_end = nil;
[self startDate:&this_start andEndDate:&this_end ofWeekOn:[NSDate date]];
下周:
NSDate *lastWeekDate = [this_start dateByAddingTimeInterval:-10];
NSDate *last_start = nil, *last_end = nil;
[self startDate:&last_start andEndDate:&last_end ofWeekOn:lastWeekDate];
现在你拥有了所有这些。
答案 11 :(得分:1)
Swift 3
首先找到当前日期...
let today = Date()
let gregorian = Calendar(identifier: .gregorian)
var weekdayComponents: DateComponents? = gregorian.dateComponents([.weekday], from: today)
周日= 1,周一= 2,周二= 3,周三= 4,周四= 5,周五= 6,周六= 7。
var componentsToSubtract = DateComponents()
componentsToSubtract.day = (0 - (weekdayComponents?.weekday!)!) + 2
beginningOfWeek = gregorian.date(byAdding: componentsToSubtract, to: today)
var componentsToAdd: DateComponents? = gregorian.dateComponents([.day], from: beginningOfWeek!)
componentsToAdd?.day = 6
endOfWeek = gregorian.date(byAdding: componentsToAdd!, to: beginningOfWeek!)
let components: DateComponents? = gregorian.dateComponents([.month], from: beginningOfWeek!)
let month: Int? = components?.month
let components1: DateComponents? = gregorian.dateComponents([.month], from: endOfWeek!)
let month1: Int? = components1?.month
print("\(month) - \(month1)")
showDate(start:beginningOfWeek!, end:endOfWeek!, strtMn:month!, endMn:month1!)
func showDate(start:Date, end:Date, strtMn:Int, endMn:Int) {
if strtMn == endMn{
let formatter = DateFormatter()
formatter.dateFormat = "MMM dd"
let stringFromDate: String = formatter.string(from: start)
let formatter1 = DateFormatter()
formatter1.dateFormat = "dd"
let stringFromDate1: String = formatter1.string(from: end)
print("\(stringFromDate) - \(stringFromDate1)")
lblDate.text = "\(stringFromDate) - \(stringFromDate1)"
}
else{
let formatter = DateFormatter()
formatter.dateFormat = "MMM dd"
let stringFromDate: String = formatter.string(from: start)
let formatter1 = DateFormatter()
formatter1.dateFormat = "MMM dd"
let stringFromDate1: String = formatter1.string(from: end)
print("\(stringFromDate) - \(stringFromDate1)")
lblDate.text = "\(stringFromDate) - \(stringFromDate1)"
}
}
为下一个和上一个....
@IBAction func week_CalendarActionEvents(_ sender: UIButton) {
let gregorian = Calendar(identifier: .gregorian)
var offsetComponents = DateComponents()
var nextStrtDate: Date?
var nextEndDate: Date?
var startDate: Date?
var endDate: Date?
startDate = beginningOfWeek
endDate = endOfWeek
if sender.tag == 1 {
offsetComponents.day = -7
}
else if sender.tag == 2 {
offsetComponents.day = 7
}
nextStrtDate = gregorian.date(byAdding: offsetComponents, to:startDate!)
startDate = nextStrtDate
beginningOfWeek = startDate
nextEndDate = gregorian.date(byAdding: offsetComponents, to: endDate!)
endDate = nextEndDate
endOfWeek = endDate
let components: DateComponents? = gregorian.dateComponents([.month], from: startDate!)
let month: Int? = components?.month
let components1: DateComponents? = gregorian.dateComponents([.month], from: endDate!)
let month1: Int? = components1?.month
print("\(month)- \(month1)")
showDate(start:startDate!, end:endDate!, strtMn:month!, endMn:month1!)
}
答案 12 :(得分:1)
您可以通过以下代码获取当前日期和日期:
NSDate *today = [NSDate date];
NSDateFormatter *dateFormat = [[[NSDateFormatter alloc] init] autorelease];
[dateFormat setDateFormat:@"EEEE"];
NSString *weekDay = [dateFormat stringFromDate:today];
[dateFormat setDateFormat:@"dd"];
NSString *thedate=[dateFormat stringFromDate:today];
//[dateFormat release];
NSLog(@"%@ %@", weekDay,thedate);
现在,你需要在其中加入一些逻辑来计算一周的开始日期和结束日期。逻辑就是这样,
如果工作日是星期一
然后
开始日期=当前日期 - 0
结束日期=当前日期+ 6
等等
我认为你可以理解它。
答案 13 :(得分:1)
Swift 3+:带有扩展程序的简单解决方案
extension Date {
var startOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 1, to: sunday)
}
var endOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 7, to: sunday)
}
var yesterdayDate: Date? {
return NSCalendar.current.date(byAdding: .day, value: -1, to: noon)!
}
var tommorowDate: Date? {
return NSCalendar.current.date(byAdding: .day, value: 1, to: noon)!
}
var previousDate: Date? {
let oneDay:Double = 60 * 60 * 24
return self.addingTimeInterval(-(Double(oneDay)))
}
var nextDate: Date? {
let oneDay:Double = 60 * 60 * 24
return self.addingTimeInterval(oneDay)
}
var noon: Date {
return NSCalendar.current.date(bySettingHour: 12, minute: 0, second: 0, of: self)!
}
var month: Int {
return Calendar.current.component(.month, from: self)
}
}
答案 14 :(得分:1)
Swift 5.x 的解决方案
创建日期扩展:
func weekPeriod() -> (startDate: Date, endDate: Date) {
let calendar = Calendar(identifier: .gregorian)
guard let sundayDate = calendar.date(from: calendar.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return (startDate: Date(), endDate: Date()) }
if calendar.isDateInToday(sundayDate) {
let startDate = calendar.date(byAdding: .day, value: -6, to: sundayDate) ?? Date()
let endDate = sundayDate
return (startDate: startDate, endDate: endDate)
}
let startDate = calendar.date(byAdding: .day, value: 1, to: sundayDate) ?? Date()
let endDate = calendar.date(byAdding: .day, value: 6, to: startDate) ?? Date()
return (startDate: startDate, endDate: endDate)
}
答案 15 :(得分:0)
在swift 3.0中
let cal = NSCalendar.current
//weekday
let weekday = cal.component(.weekday, from: Date())
var dateComp = cal.dateComponents([.hour, .minute, .second, .day, .month, .year], from: Date())
print(dateComp.day!)
//Start Date of the week - Sunday
dateComp.day = dateComp.day! - (weekday - 1)// start date of week
print(cal.date(from: dateComp)!)
//End Date of the Week - Saturday
dateComp = cal.dateComponents([.hour, .minute, .second, .day, .month, .year], from: Date())
dateComp.day = dateComp.day! + (7 - weekday)
print(cal.date(from: dateComp)!)
答案 16 :(得分:0)
如果要显示当前星期几,请使用以下代码。
override func viewDidLoad() {
super.viewDidLoad()
for dateIndex in 0..<7 {
guard let startWeek = Date().startOfWeek else { return }
let date = Calendar.current.date(byAdding: .day, value: dateIndex + 1, to: startWeek)
print(date)
}
}
extension Date {
var startOfWeek: Date? {
let gregorian = Calendar(identifier: .gregorian)
guard let sunday = gregorian.date(from: gregorian.dateComponents([.yearForWeekOfYear, .weekOfYear], from: self)) else { return nil }
return gregorian.date(byAdding: .day, value: 1, to: sunday)
}
}