我有五个wav文件。我想使用sourceDataLine从单个Java程序中连续播放它们。但是我的程序没有保持正确的顺序。任何人都可以提供我的代码段吗?
答案 0 :(得分:3)
您检查了Documentation吗?
从here:
尝试此示例import java.io.*;
import javax.sound.sampled.*;
/**
* Use SourceDataLine to read line-by-line from the external sound file.
*/
public class SoundLineTest {
public static void main(String[] args) {
SourceDataLine soundLine = null;
int BUFFER_SIZE = 64*1024; // 64 KB
// Set up an audio input stream piped from the sound file.
try {
File soundFile = new File("gameover.wav");
AudioInputStream audioInputStream = AudioSystem.getAudioInputStream(soundFile);
AudioFormat audioFormat = audioInputStream.getFormat();
DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
soundLine = (SourceDataLine) AudioSystem.getLine(info);
soundLine.open(audioFormat);
soundLine.start();
int nBytesRead = 0;
byte[] sampledData = new byte[BUFFER_SIZE];
while (nBytesRead != -1) {
nBytesRead = audioInputStream.read(sampledData, 0, sampledData.length);
if (nBytesRead >= 0) {
// Writes audio data to the mixer via this source data line.
soundLine.write(sampledData, 0, nBytesRead);
}
}
} catch (UnsupportedAudioFileException ex) {
ex.printStackTrace();
} catch (IOException ex) {
ex.printStackTrace();
} catch (LineUnavailableException ex) {
ex.printStackTrace();
} finally {
soundLine.drain();
soundLine.close();
}
}
}