在OpenCV中,我使用std::vector<std::vector<cv::Point>>::const_iterator
,就像这里的代码一样:
std::vector<std::vector<cv::Point>> contours;
cv::findContours(contour,contours,CV_RETR_TREE,CV_CHAIN_APPROX_SIMPLE);
std::vector<std::vector<cv::Point>>::const_iterator itContours = contours.begin();
while(itContours != contours.end())
{
if(Condition1)
itContours = contours.erase(itContours);
else if(Condition2)
itContours = contours.erase(itContours);
else if(Condition3)
itContours = contours.erase(itContours);
else
++itContours;
}
但是现在我开始使用EmguCV,但我找不到像上面的代码那样做。我该怎么办?
答案 0 :(得分:1)
查看EMGU.Examples文件夹中的形状检测示例。它向您展示了如何处理轮廓。我已经复制了下面的相关代码供您参考,但最好还是看一下这个例子。
#region Find triangles and rectangles
List<Triangle2DF> triangleList = new List<Triangle2DF>();
List<MCvBox2D> boxList = new List<MCvBox2D>(); //a box is a rotated rectangle
using (MemStorage storage = new MemStorage()) //allocate storage for contour approximation
for (Contour<Point> contours = cannyEdges.FindContours(Emgu.CV.CvEnum.CHAIN_APPROX_METHOD.CV_CHAIN_APPROX_SIMPLE, Emgu.CV.CvEnum.RETR_TYPE.CV_RETR_LIST, storage); contours != null; contours = contours.HNext)
{
Contour<Point> currentContour = contours.ApproxPoly(contours.Perimeter * 0.05, storage);
if (currentContour.Area > 250) //only consider contours with area greater than 250
{
if (currentContour.Total == 3) //The contour has 3 vertices, it is a triangle
{
Point[] pts = currentContour.ToArray();
triangleList.Add(new Triangle2DF(
pts[0],
pts[1],
pts[2]
));
}
else if (currentContour.Total == 4) //The contour has 4 vertices.
{
#region determine if all the angles in the contour are within [80, 100] degree
bool isRectangle = true;
Point[] pts = currentContour.ToArray();
LineSegment2D[] edges = PointCollection.PolyLine(pts, true);
for (int i = 0; i < edges.Length; i++)
{
double angle = Math.Abs(
edges[(i + 1) % edges.Length].GetExteriorAngleDegree(edges[i]));
if (angle < 80 || angle > 100)
{
isRectangle = false;
break;
}
}
#endregion
if (isRectangle) boxList.Add(currentContour.GetMinAreaRect());
}
}
}
#endregion
如果您需要任何其他帮助,如果弹出任何错误,请告诉我,
干杯,
克里斯