任何人都知道在哪里可以获得使用邻接列表来表示无向图的通用示例代码？
图形数据来自.txt文件：节点在第一行指定，用空格分隔。边缘在以下行中指定，每个边缘在单独的行上。
喜欢这个......
1 2 3 4 5 6 7 8 9
1 2
1 4
1 3
2 4
2 5
3 6
4 6
5 7
5 8
6 9
7 9
8 9
我的.txt文件未与图表方法连接。我也遇到了以下NPE错误：
Error: java.lang.NullPointerException
创建邻接列表＆amp;为无向图执行标准Graph ADT方法。
//TON of imports up here (removed for now)
class Graph<V> implements GraphADT1 <V>{
// Map of adjacency lists for each node
private HashMap<Integer, LinkedList<Integer>> adj;
private ArrayList<V> vertices;
private HashMap<V, LinkedHashSet<V>> neighbors;
private HashMap<V, Set<V>> neighborsView;
private int edgeCount;
public Graph(int[] nodes) {
vertices = new ArrayList<V>();
neighbors = new HashMap<V, LinkedHashSet<V>>();
neighborsView = new HashMap<V, Set<V>>();
adj = new HashMap<Integer, LinkedList<Integer>>();
for (int i = 0; i < nodes.length; ++i) {
adj.put(i, new LinkedList<Integer>());
}
}
//Add Vertex Method
public void addVertex(V vid) {
vertices.add(vid);
LinkedHashSet<V> neighborV = new LinkedHashSet<V>();
neighbors.put(vid, neighborV);
neighborsView.put(vid, Collections.unmodifiableSet(neighborV));
}
// Removes Vertex Method
public void removeVertex(V vid) {
if(vertices.remove(vid)) {
LinkedHashSet<V> neighborV = neighbors.remove(vid);
for(V uid : neighborV) {
LinkedHashSet<V> neighborU = neighbors.get(uid);
neighborU.remove(vid);
--edgeCount;
}
neighborsView.remove(vid);
} else {
throw new NoSuchElementException("no such vertex");
}
}
//Add Edge Method
public void addEdge(V uid, V vid) {
LinkedHashSet<V> neighborU = neighbors.get(uid);
LinkedHashSet<V> neighborV = neighbors.get(vid);
if(neighborU == null) throw new NoSuchElementException("first argument not in graph");
if(neighborV == null) throw new NoSuchElementException("second argument not in graph");
if(neighborU.add(vid) && neighborV.add(uid)) {
++edgeCount;
}
}
//Remove Edge Method
public void removeEdge(V uid, V vid) {
LinkedHashSet<V> neighborU = neighbors.get(uid);
LinkedHashSet<V> neighborV = neighbors.get(vid);
if(neighborU == null) throw new NoSuchElementException("first argument not in graph");
if(neighborV == null) throw new NoSuchElementException("second argument not in graph");
if(neighborU.remove(vid) && neighborV.remove(uid)) {
--edgeCount;
} else {
throw new NoSuchElementException("no edge between vertices");
}
}
public void addNeighbor(int neighborV, int neighborU) {
adj.get(neighborV).add(neighborU);
}
public List<Integer> getNeighbors(int v) {
return adj.get(v);
}
public static void main(String[] args) {
try {
File file = new File("data.txt");
InputStreamReader streamReader = new InputStreamReader(
new FileInputStream(file));
BufferedReader br = new BufferedReader(streamReader);
String line = br.readLine();
if (line != null) {
// read nodes
String[] nodeNames = line.split(" ");
int[] nodes = new int[nodeNames.length];
for (int i = 0; i < nodes.length; ++i) {
nodes[i] = Integer.parseInt(nodeNames[i]);
}
// create graph
Graph V = new Graph(nodes);
// read edges
while ((line = br.readLine()) != null) {
String[] tokens = line.split(" ");
int neighborV = Integer.parseInt(tokens[0]);
int neighborU = Integer.parseInt(tokens[1]);
// we add neighbor to each node in both directions.
V.addNeighbor(neighborV, neighborU);
V.addNeighbor(neighborU, neighborV);
}
}
br.close();
} catch (FileNotFoundException ex) {
ex.printStackTrace();
} catch (IOException ex) {
ex.printStackTrace();
} catch (Exception e) {
System.out.println("Error: " + e);
}
}
public Iterator<?> iteratorBFS(Object startVertex) {
return null;
}
public Iterator<?> iteratorDFS(Object startVertex) {
return null;
}
public boolean isEmpty() {
return size() == 0;
}
public boolean isConnected() {
return false;
}
public int size() {
return 0;
}
}
答案 0 :(得分：11)
您可以将图表括在课堂中：
class Graph {
//Map of adjacency lists for each node
Map<Integer, List<Integer>> adj;
public Graph(int[] nodes) {
//your node labels are consecutive integers starting with one.
//to make the indexing easier we will allocate an array of adjacency one element larger than necessary
adj = new HashMap<Integer, LinkedList<Integer>>();
for (int i = 0; i < nodes.length; ++i) {
adj.put(i, new LinkedList<Integer>());
}
}
public addNeighbor(int v1, int v2) {
adj.get(v1).add(v2);
}
public List<Integer> getNeighbors(int v) {
return adj.get(v);
}
}
然后或多或少地阅读它：
public static void main(String[] args) {
try {
BufferedReader br = new BufferedReader(new StreamReader(System.in));
String line = br.readLine();
if (line != null) {
//read nodes
String[] nodeNames = line.split(" ");
int[] nodes = new int[nodeNames.length]
for (int i = 0; i < nodes.length; ++i) {
nodes[i] = Integer.parseInt(nodeNames[i]);
}
//create graph
Graph g = new Graph(nodes);
//read edges
while((line = br.readLine()) != null) {
String[] tokens = line.split(" ");
int v1 = Integer.parseInt(tokens[0]);
int v2 = Integer.parseInt(tokens[1]);
//we add neighbor to each node in both directions.
g.addNeighbor(v1, v2);
g.addNeighbor(v2, v1);
}
}
br.close();
}
catch(exceptions) {
handle them
}
}
答案 1 :(得分：2)
public static void main(String [] Args){
try {
Scanner s = new Scanner(new File("your file.txt"));
StringTokenizer t = new StringTokenizer(s.nextLine());
Hashtable<Integer,Node> nodes = new Hashtable<Integer,Node>();
while(t.hasMoreTokens()){
int id = Integer.parseInt(t.nextToken());
nodes.put(id, new Node(id));
}
while(s.hasNextInt()){
Node e1 = nodes.get(s.nextInt());
Node e2 = nodes.get(s.nextInt());
e1.adjacent.add(e2);
e2.adjacent.add(e1);
}
\\now you can use the nodes Map above to retrieve nodes or to get a list:
List<Node> adjencyNodeList = new ArrayList(nodes.values());
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
}
class Node {
int id;
List<Node> adjacent = new ArrayList<Node>();
public Node(int id){
this.id = id;
}
}