我只是通过构建这个简单的程序来确定我理解继承,其中Dog继承自哺乳动物。编译时我收到错误。所有它应该做的是进入哺乳动物和狗,树皮的构造,然后进入哺乳动物和狗的析构。我很抱歉在帖子中缩进了一下,它在Visual Studio中组织得很好。
#include <iostream>
#include <string>
using namespace std;
class Mammal
{
public:
Mammal();
Mammal(int age);
Mammal(int age, int mammal);
~Mammal();
int getAge() {return itsAge;};
int getWeight() {return itsWeight;};
void setAge(int x) {itsAge = x;};
void setWeight(int x) {itsWeight = x;};
void speak() {cout << "MAMMALALALALALLLL!" << endl;};
private:
int itsAge, itsWeight;
};
class Dog : public Mammal
{
public:
Dog();
Dog(int age);
Dog(int age, int weight);
Dog(int age, int weight, string breed);
~Dog();
void setBreed(string breed) {itsBreed = breed;};
string getBreed() {return itsBreed;};
void bark() {cout << "Bark!" << endl;};
private:
string itsBreed;
};
Mammal::Mammal()
{
cout << "Mammal constructor." << endl;
setAge(0);
setWeight(0);
}
Mammal::Mammal(int age)
{
cout << "Mammel(int) constructor." << endl;
setAge(age);
setWeight(0);
}
Mammal::Mammal(int age, int weight)
{
cout << "Mammal(int, int) constructor." << endl;
setAge(age);
setWeight(weight);
}
Mammal::~Mammal()
{
cout << "Mammal deconstructor." << endl;
}
Dog::Dog():
Mammal()
{
cout << "Dog constructor." << endl;
setBreed("");
}
Dog::Dog(int age):
Mammal(age)
{
cout << "Dog(int) constructor." << endl;
setBreed("");
}
Dog::Dog(int age, int weight):
Mammal(age, weight)
{
cout << "Dog(int, int) constructor." << endl;
setBreed("");
}
Dog::Dog(int age, int weight, string breed):
Mammal(age, weight)
{
cout << "Dog(int, int, string) constructor." << endl;
setBreed(breed);
}
int main()
{
Dog Goldie(5, 50, "Lab");
Goldie.bark();
system("PAUSE");
return 0;
}
编译器的输出如下:
1>ClCompile:
1> main.cpp
1>main.obj : error LNK2019: unresolved external symbol "public: __thiscall Dog::~Dog(void)" (??1Dog@@QAE@XZ) referenced in function _main
1>c:\users\austin\documents\visual studio 2010\Projects\Inheritance\Debug\Inheritance.exe : fatal error LNK1120: 1 unresolved externals
1>
1>Build FAILED.
1>
1>Time Elapsed 00:00:00.31
========== Build: 0 succeeded, 1 failed, 0 up-to-date, 0 skipped ==========
答案 0 :(得分:5)
您为Dog
类声明了析构函数,但没有定义它
你也应该定义它。
Dog::~Dog(){}
gcc上的错误,清楚地告诉:
修改后的代码prog.cpp :(。text + 0xf54):对狗::〜狗()的未定义引用 prog.cpp :(。text + 0xfc3):未定义引用Dog :: ~Dog()
答案 1 :(得分:3)
您尚未为Dog
:
Dog::~Dog()
{
cout << "Dog destructor." << endl;
}