Question

我正在使用cocos2d并拥有许多精灵和身体。每个精灵都有自己的身体，每种精灵都有一个标签。（见下）。

当2个精灵相互接触时，我可以发现它并且我希望它们消失。

问题是我有很多来自同一类型的精灵（具有相同的标签）所以当我清理一个精灵时，它会清理最后创建的精灵，而不是我想要的精灵。

我创建同一种精灵的函数是：

-(void)fruit1:(int) randomForCoordinates
{

    //define sprite
    fruit1=[CCSprite spriteWithFile:@"fruit1.png"];
    fruit1.tag=2;
    fruit1.position=ccp(randomForCoordinates,500);
    //add fruit
    b2BodyDef spriteBodyDef;
    spriteBodyDef.type =b2_dynamicBody;
    spriteBodyDef.position.Set(fruit1.position.x/PTM_RATIO,fruit1.position.y/PTM_RATIO);
    spriteBodyDef.userData = fruit1;
    fruit1body = world->CreateBody(&spriteBodyDef);

    b2PolygonShape spriteShape; //b2polygon-for box shape
    spriteShape.SetAsBox(fruit1.contentSize.width/PTM_RATIO/2,fruit1.contentSize.height/PTM_RATIO/2); //for b2polygon
    b2FixtureDef spriteShapeDef;
    spriteShapeDef.shape = &spriteShape;
    spriteShapeDef.density = 10.0;
    spriteShapeDef.isSensor = false;
    fruit1body->CreateFixture(&spriteShapeDef);
    [self addChild:fruit1];

}

标记为2。当我看到与此联系时：

//cotact listener 
    std::vector<MyContact>::iterator pos;
    for(pos = _contactListener->_contacts.begin(); pos != _contactListener->_contacts.end(); ++pos) 
    {
        MyContact contact = *pos;
        b2Body *bodyA=contact.fixtureA->GetBody();
        b2Body *bodyB=contact.fixtureB->GetBody();

        //check if collision between to bodies
        if( bodyA->GetUserData() !=NULL && bodyB->GetUserData() !=NULL)    //if ((contact.fixtureA == _bottomFixture && contact.fixtureB == _ballFixture) ||(contact.fixtureA == _ballFixture && contact.fixtureB == _bottomFixture))
        {
            CCSprite *actor = (CCSprite*)bodyA->GetUserData(); 
            CCSprite *actorb = (CCSprite*)bodyB->GetUserData();


            //touch
            if ([actorb tag] == 2  && [actor tag]== 1)
            {
            [fruit1.parent removeChild:fruit1 cleanup:YES];
            NSLog(@"touch1");

            }

现在消失的精灵不是那里触及的精灵，而是那个在他身后创造的精灵......

我如何擦除一个SPECIFIC精灵 - 刚刚触及另一个精灵？不是最后一个创建的？

非常感谢

Answer 1

如果有两个精灵碰撞，你可以删除下面的任何一个精灵：

 if( bodyA->GetUserData() !=NULL && bodyB->GetUserData() !=NULL)    //if ((contact.fixtureA == _bottomFixture && contact.fixtureB == _ballFixture) ||(contact.fixtureA == _ballFixture && contact.fixtureB == _bottomFixture))
    {
        CCSprite *actor = (CCSprite*)bodyA->GetUserData(); 
        CCSprite *actorb = (CCSprite*)bodyB->GetUserData();


        //touch
        if ([actorb tag] == 2  && [actor tag]== 1)
        {

            [self removeChild:actor cleanup:YES];
            //(or)
            [self removeChild:actorb cleanup:YES];


        NSLog(@"touch1");

        }

从屏幕清除特定的精灵

1 个答案: