我正在尝试Coq,但我不完全确定我在做什么。是:
Theorem new_theorem : forall x, P:Prop /\ Q:Prop
相当于:
∀x ( P(x) and Q(x) )
编辑:我认为他们是。
答案 0 :(得分:3)
您是否遇到语法问题?
$ coqtop
Welcome to Coq 8.1pl3 (Dec. 2007)
Coq < Section Test.
Coq < Variable X:Set.
X is assumed
Coq < Variables P Q:X -> Prop.
P is assumed
Q is assumed
Coq < Theorem forall_test: forall x:X, P(x) /\ Q(x).
1 subgoal
X : Set
P : X -> Prop
Q : X -> Prop
============================
forall x : X, P x /\ Q x
forall_test <
答案 1 :(得分:2)
好吧,回答你的问题:
Section test.
Variable A : Type. (* assume some universe A *)
Variable P Q : A -> Prop. (* and two predicates over A, P and Q *)
Goal forall x, P x /\ Q x. (* Ax, ( P(x) and Q(x) ) *)
End test.