Question

我的页面上有2个ajax函数。单击网格内的链接时单击一个，单击按钮时单个链接。来自网格的那个完美无缺。但是，单击按钮的功能每次都会产生错误。

有人可以告诉我这里我出错了吗？我将不胜感激任何帮助。这是失败的：

    function createSource() {
        $.ajax({
            type: "POST",
            url: "Test.aspx/createSource",
            data: '{"schoolID":"' + $('#ddSchools').val() + '","vendor":"' + $('#txtVendor').val() + '","tSource":"' +  $('#txtTSource').val()+ '"}',
            contentType: "application/json",
            dataType: "json",
            success: function (msg) {
                alert(msg.d);
            },
            error: function (xhRequest, ErrorText, thrownError) {
                alert(thrownError);
            }
        });
    }

Web方法会有更多的代码，但无论如何我似乎无法打它。这是webmethod：

[WebMethod]
[System.Web.Script.Services.ScriptMethod(UseHttpGet = true)]
public static string createSource(int schoolId, string vendor, string tSource)
{
    try
    {
        string status = "This is a test string!";

        return status;
    }
    catch
    {
        throw new Exception("Could not create source code!");
    }
}

另外，我如何才能获得导致此功能失败的确切错误？

提前感谢您的帮助!!

好吧所以我想问题在哪里，但我仍然没有解决方案。实际上代码没有任何问题。我将代码插入document.ready并正确解雇。但是，只要单击按钮，它就不会正确触发。按钮也没什么特别的。这是一个简单的输入按钮。

<input id="cmdSubmit_Create" value="Submit" type="submit" />

任何想法？

作为参考，我将把有效的代码放在document.ready：

上

$(document).ready(function () {
    $.ajax({
            type: "POST",
            url: "Test.aspx/createSource",
            data: '{"schoolId":"2236","vendor":"test","tsource":"test1234"}',
            contentType: "application/json",
            dataType: "json",
            success: function (msg) {
                alert(msg.d);
            },
            error: function (jqXHR, textStatus, errorThrown) {
                alert("status: " + textStatus + " errorThrown: " + errorThrown);
            },
            complete: function (jqXHR, textStatus) {
                alert("status: " + textStatus);
            }
        });
});

[WebMethod]
public static string helloWorld(string schoolId, string vendor,string tsource)
{
    try
    {
        StringBuilder sb = new StringBuilder();
        sb.Append("Hello World! " + schoolId + '-' + vendor + '-' + tsource);

        return sb.ToString();
    }
    catch
    {
        throw new Exception("Could not create source code!");
    }
}

如果我尝试在单击cmdSubmit_Create时调用相同的webmethod它不起作用：

       $('#cmdSubmit_Create').click(function () {
        $.ajax({
            type: "POST",
            url: "Test.aspx/helloWorld",
            data: '{"schoolId":"2236","vendor":"test","tsource":"test1234"}',
            contentType: "application/json",
            dataType: "json",
            success: function (msg) {
                alert(msg.d);
            },
            error: function (xhr, status, error) {
                alert('error' + error)
            }
        });

Answer 1

您的服务需要GET UseHttpGet = true 正如您所做的那样POST尝试

type: "GET",

Answer 2

使用以下代码

$('#cmdSubmit_Create').click(function () {
    $.ajax({
        type: "POST",
        url: "Test.aspx/helloWorld",
        data: '{"schoolId":"2236","vendor":"test","tsource":"test1234"}',
        contentType: "application/json",
        dataType: "json",
        success: function (msg) {
            alert(msg.d);
        },
        error: function (xhr, status, error) {
            alert('error' + error)
        }
    });
    return false;
});

http://cmsnsoftware.blogspot.com/2011/01/how-to-call-csharp-function-in-ajax.html

webmethod的AJAX功能不起作用

2 个答案: