我知道这个问题已被问到很多,但我无法解决我的问题。 我想在不重新加载页面的情况下运行PHP函数。为什么这不起作用? php文件是indexTest.php。
页面只是滚动到顶部,没有任何效果。
我是AJAX的新手,所以我真的不知道该怎么做。
HTML:
<script type="text/javascript">
function submitdata()
{
var nameForm=document.getElementById( "nameForm" );
var emailForm=document.getElementById( "emailForm" );
var messageForm=document.getElementById( "messageForm" );
$.ajax({
type: 'post',
url: 'indexTest.php',
data: {
name:nameForm,
email:emailForm,
message:messageForm
},
});
return false;
}
</script>
<form onsubmit="return submitdata()" method="POST" id="contactForm">
<input spellcheck="false" class="first" type="text" name="name" placeholder="name" id="nameForm">
<input spellcheck="false" class="first" type="text" name="email" placeholder="email" id="emailForm">
<textarea rows="8" spellcheck="false" class="last" type="text" name="message" placeholder="message" id="messageForm"></textarea>
<input type="submit" name="submit" value="" id="button">
</form>
PHP:
<?php
if(isset($_POST['submit'])){
$to = "*"; // this is your Email address
$from = $_POST['email']; // this is the sender's Email address
if (!filter_var($email, FILTER_VALIDATE_EMAIL)) {
echo "Invalid email format";
};
$first_name = $_POST['name'];
$subject = "Form submission";
$subject2 = "Copy of your form submission";
$message = "Email from: " . $from . "\n\n" . $first_name . " wrote the following:" . "\n\n" . $_POST['message'];
$message2 = "Here is a copy of your message " . $first_name . "\n\n" . $_POST['message'];
$headers = "From:" . $from;
$headers2 = "From:" . $to;
mail($to,$subject,$message,$headers);
mail($from,$subject2,$message2,$headers2); // sends a copy of the message to the sender
echo '<script language="javascript">';
echo 'alert("message successfully sent")';
echo '</script>';
// You can also use header('Location: thank_you.php'); to redirect to another page.
}
?>
答案 0 :(得分:0)
问题在于,当您真正想要通过AJAX发布时,您正在通过表单本身进行发布。基本上,因为您在onsubmit
中调用JavaScript函数,JavaScript将在添加中运行到默认表单提交。
您需要做的是使用e.preventDefault();
停用默认表单提交,然后运行JavaScript 而不是:
$("#contactForm").submit(function(e) {
e.preventDefault();
submitdata();
});
希望这有帮助! :)