Question

有人能找出这段代码中的错误吗？我试图调用我的API控制器返回JsonObject。它击中控制器，结果显示在Chrome＆gt;中预习。但是，当我尝试访问成功函数时，它显示未定义。

$(document).ready(function () {

CallService();
});

function CallService() {
 $.ajax({
    type: "GET",
    url: "http://localhost:8080/Java/Controller/Method",
    contentType: "application/json; charset=utf-8",
    dataType: "script",
    success: function (data) {

        alert('success '+ data);

    },
    error: function (data) {
        alert('error ' + data);
    }
 });
}

有趣的是，如果我输入dataType：＆＃34;脚本＆＃34;我只能点击控制器。在json或jsonp的情况下。我无法击中控制器上的事件。

修改

使用dataType控制台登录：＆＃34; jsonp＆＃34;

  object {readyState: 4, getResponseHeader: function, getAllResponseHeaders: function,     setRequestHeader: function, overrideMimeType: function…}
  abort: function (a){var b=a||u;return i&&i.abort(b),x(0,b),this}
  always: function (){return e.done(arguments).fail(arguments),this}
  complete: function (){if(h){var d=h.length;!function f(b){n.each(b,function(b,c){var d=n.type(c);"function"===d?a.unique&&k.has(c)||h.push(c):c&&c.length&&"string"!==d&&f(c)})}(arguments),b?e=h.length:c&&(g=d,j(c))}return this}
  done: function (){if(h){var d=h.length;!function f(b){n.each(b,function(b,c){var d=n.type(c);"function"===d?a.unique&&k.has(c)||h.push(c):c&&c.length&&"string"!==d&&f(c)})}(arguments),b?e=h.length:c&&(g=d,j(c))}return this}
   error: function (){if(h){var d=h.length;!function f(b){n.each(b,function(b,c){var d=n.type(c);"function"===d?a.unique&&k.has(c)||h.push(c):c&&c.length&&"string"!==d&&f(c)})}(arguments),b?e=h.length:c&&(g=d,j(c))}return this}
   fail: function (){if(h){var d=h.length;!function f(b){n.each(b,function(b,c){var d=n.type(c);"function"===d?a.unique&&k.has(c)||h.push(c):c&&c.length&&"string"!==d&&f(c)})}(arguments),b?e=h.length:c&&(g=d,j(c))}return this}
  getAllResponseHeaders: function (){return 2===t?f:null}
  getResponseHeader: function (a){var b;if(2===t){if(!j){j={};while(b=Dc.exec(f))j[b[1].toLowerCase()]=b[2]}b=j[a.toLowerCase()]}return null==b?null:b}
  overrideMimeType: function (a){return t||(k.mimeType=a),this}
  pipe: function (){var a=arguments;return n.Deferred(function(c){n.each(b,function(b,f){var g=n.isFunction(a[b])&&a[b];e[f[1]](function(){var a=g&&g.apply(this,arguments);a&&n.isFunction(a.promise)?a.promise().done(c.resolve).fail(c.reject).progress(c.notify):c[f[0]+"With"](this===d?c.promise():this,g?[a]:arguments)})}),a=null}).promise()}
   progress: function (){if(h){var d=h.length;!function f(b){n.each(b,function(b,c){var d=n.type(c);"function"===d?a.unique&&k.has(c)||h.push(c):c&&c.length&&"string"!==d&&f(c)})}(arguments),b?e=h.length:c&&(g=d,j(c))}return this}
   promise: function (a){return null!=a?n.extend(a,d):d}
   readyState: 4
   setRequestHeader: function (a,b){var c=a.toLowerCase();return t||(a=s[c]=s[c]||a,r[a]=b),this}
   state: function (){return c}
   status: 200
   statusCode: function (a){var b;if(a)if(2>t)for(b in a)q[b]=[q[b],a[b]];else v.always(a[v.status]);return this}
   statusText: "success"
   success: function (){if(h){var d=h.length;!function f(b){n.each(b,function(b,c){var d=n.type(c);"function"===d?a.unique&&k.has(c)||h.push(c):c&&c.length&&"string"!==d&&f(c)})}(arguments),b?e=h.length:c&&(g=d,j(c))}return this}
   then: function (){var a=arguments;return n.Deferred(function(c){n.each(b,function(b,f){var g=n.isFunction(a[b])&&a[b];e[f[1]](function(){var a=g&&g.apply(this,arguments);a&&n.isFunction(a.promise)?a.promise().done(c.resolve).fail(c.reject).progress(c.notify):c[f[0]+"With"](this===d?c.promise():this,g?[a]:arguments)})}),a=null}).promise()}
   __proto__: Object

Answer 1

function CallService() {
  $.ajax({
  type: "GET",
  url: "http://localhost:8080/Java/Controller/Method",
  contentType: "application/json; charset=utf-8",
  success: function (data) {
    data = jQuery.parseJSON(data.d)
    alert('success '+ data[0].yourvalues);

  },
  error: function (data) {
    alert('error ' + data);
}
});
}

Answer 2

试试这个：

console.log(data);

它在您的控制台中显示jsonObject。

如果您想提醒数据，请尝试以下操作：

alert(data.jsonObectName[index].attributeName);

此处索引是对象索引，即以0开头，属性名称是对象

中的值名称

$.ajax({
type: "GET",
url: "http://localhost:8080/Java/Controller/Method",
contentType: "application/json; charset=utf-8",
dataType: "script",
success: function (data) {
    console.log(data);
    alert('success '+ data.jsonObectName[index].attributeName);

},
error: function (data) {
    console.log(data);
    alert('error ' + data.jsonObectName[index].attributeName);
}

}）;

Answer 3

您的AJAX成功方法中有对象。然后你可以从响应中绑定数据。

在这里供你参考我从服务器附加了简单的JSONP响应并绑定了UserInterface中的值。

$.ajax({
type: 'GET',
url: 'http://githubbadge.appspot.com/Jebasuthan',
dataType: 'jsonp',
success: function (json) {
    console.log(json);
    var result = '<h3>Name: ' + json.user.login + '</h3>' +
                 '<p>Forked Repository: ' + json.fork_repos + '</p>' +
                 '<p>Languages: ' + json.languages + '</p>' +
                 '<p>Email-Id: ' + json.user.email + '</p>' +
                 '<p>Location: ' + json.user.location + '</p>' +
                 '<p>Last Updated Date: ' + json.user.updated_at + '</p>' +
                 '<p>Blog: <a target="_blank" href=' + json.user.blog + '>' + json.user.blog + '</a></p>';
      $('#badge').append(result);
  }
});

Demo

JQuery ajax函数不起作用

3 个答案: