我一直在尝试使用这里的样本:
J2ME: Convert transparent PNG image to grayscale
在这里:
http://www.java2s.com/Code/Java/Collections-Data-Structure/intarraytobytearray.htm
将Bitmap图像对象动态转换为灰度,但当我尝试将字节重新编码为图像时遇到问题,我得到以下错误/堆栈:
(Suspended (exception IllegalArgumentException))
EncodedImage.createEncodedImage(byte[], int, int, String) line: 367
EncodedImage.createEncodedImage(byte[], int, int) line: 279
ScreenTemp.getGrayScaleImage(Bitmap) line: 404
这是我正在尝试的代码:
Bitmap btemp = getGrayScaleImage(Bitmap.getBitmapResource("add.png"));
BitmapField bftemp = new BitmapField(btemp, BitmapField.FOCUSABLE | BitmapField.FIELD_HCENTER | BitmapField.FIELD_VCENTER);
add(bftemp);
public Bitmap getGrayScaleImage(Bitmap image) {
int width = image.getWidth();
int height = image.getHeight();
int[] rgbData = new int[width * height];
image.getARGB(rgbData, 0, width, 0, 0, width, height);
for (int x = 0; x < width*height ; x++) {
rgbData[x] = getGrayScale(rgbData[x]);
}
byte[] b = int2byte(rgbData);
final EncodedImage jpegPic = EncodedImage.createEncodedImage(b, 0, b.length);
return jpegPic.getBitmap();
}
private int getGrayScale(int c) {
int[] p = new int[4];
p[0] = (int) ((c & 0xFF000000) >>> 24); // Opacity level
p[1] = (int) ((c & 0x00FF0000) >>> 16); // Red level
p[2] = (int) ((c & 0x0000FF00) >>> 8); // Green level
p[3] = (int) (c & 0x000000FF); // Blue level
int nc = p[1] / 3 + p[2] / 3 + p[3] / 3;
// a little bit brighter
nc = nc / 2 + 127;
p[1] = nc;
p[2] = nc;
p[3] = nc;
int gc = (p[0] << 24 | p[1] << 16 | p[2] << 8 | p[3]);
return gc;
}
private static byte[] int2byte(int[] src) {
int srcLength = src.length;
byte[]dst = new byte[srcLength << 2];
for (int i=0; i<srcLength; i++) {
int x = src[i];
int j = i << 2;
dst[j++] = (byte) ((x >>> 0) & 0xff);
dst[j++] = (byte) ((x >>> 8) & 0xff);
dst[j++] = (byte) ((x >>> 16) & 0xff);
dst[j++] = (byte) ((x >>> 24) & 0xff);
}
return dst;
}
任何帮助都会很棒!
谢谢, 贾斯汀
编辑: 感谢以下信息,我能解决这个问题。这是代码。你不再需要int2byte,这里是更新的getGrayScaleImage方法:
public Bitmap getGrayScaleImage(Bitmap image) {
int width = image.getWidth();
int height = image.getHeight();
int[] rgbData = new int[width * height];
image.getARGB(rgbData, 0, width, 0, 0, width, height);
for (int x = 0; x < width*height ; x++) {
rgbData[x] = getGrayScale(rgbData[x]);
}
byte[] b = int2byte(rgbData);
Bitmap bit = new Bitmap(width, height);
bit.setARGB(rgbData, 0, width, 0, 0, width, height);
return bit;
}
答案 0 :(得分:4)
如果无法识别图像格式,则会抛出
IllegalArgumentException
。
你为什么要摆弄EncodedImage?您似乎应该能够创建第二个Bitmap并使用setARGB()
。
答案 1 :(得分:2)
扩展Scott W
回答。
EncodedImage.createEncodedImage(byte[] data, int offset, int length)
需要支持图像类型的字节数组(TIFF,BMP,JPEG,GIF,WBMP或PNG)。例如,如果您打开JPEG图像文件,读取文件字节,那么就可以使用获取的字节来创建EncodedImage
(实际上它将是JPEGEncodedImage
。
因此,Scott W
表示您应该使用Bitmap.setARGB()
生成的字节数组,以便Bitmap
转换数据。
然后,如果你需要将图像保存为JPEG文件,你可以像这样使用smth:
JPEGEncodedImage eImage = JPEGEncodedImage.encode(bitmap, 75);
byte[] fileData = eImage.getData();
// open a FileConnection and write the fileData