Question

我是 pygame 的新手，试图创建一只飞扬的小鸟。到目前为止，我已经编写了以下代码。 https://gist.github.com/Devansha2007/fa0e5554547e6b1395e3bf3783a4c53d

import pygame
import random
pygame.init()
surface = pygame.display.set_mode((320, 568))
bg = pygame.image.load('bg.png')
bird = pygame.image.load('player.png')
pole_width = 70
pole_gap = 100
pole_x = 320
top_pole_height = random.randint(100, 400)
pole_color = (220, 85, 57)
bird_x = 0
bird_y = 0
score = 0
clock = pygame.time.Clock()
while True:
    pygame.event.get()
    keys = pygame.key.get_pressed()
    if keys[pygame.K_DOWN]:
        bird_y = bird_y + 6
    elif keys[pygame.K_UP]:
        bird_y = bird_y - 6
    surface.blit(bg, (0, 0))
    surface.blit(bird, (bird_x, bird_y))
    pygame.draw.rect(surface, pole_color, pygame.Rect(pole_x, 0, pole_width, top_pole_height))
    # pole_x = pole_x - 500
    pygame.display.flip()
    pygame.display.update()
    clock.tick(60)

Answer 1

矩形超出边界，因为 pole_x = pole_x - 500 和初始 x 坐标。删除 pole_x = pole_x - 500 并更改初始 x 坐标：

pole_x = 320 - pole_width

while True:
    pygame.event.get()
    keys = pygame.key.get_pressed()
    if keys[pygame.K_DOWN]:
        bird_y = bird_y + 6
    elif keys[pygame.K_UP]:
        bird_y = bird_y - 3
    surface.blit(bg, (0, 0))
    surface.blit(bird, (bird_x, bird_y))
    
    # pole_x = pole_x - 500 <-- remove or change this
    
    pygame.draw.rect(surface, pole_color, pygame.Rect(pole_x, 0, pole_width, top_pole_height))
    pygame.display.flip()
    pygame.display.update()
    clock.tick(60)

如果要缓慢平滑地移动矩形，请更改移动：

~~pole_x = pole_x - 500~~

pole_x -= 1

应用循环：

while True:
    pygame.event.get()
    keys = pygame.key.get_pressed()
    if keys[pygame.K_DOWN]:
        bird_y = bird_y + 6
    elif keys[pygame.K_UP]:
        bird_y = bird_y - 3
    surface.blit(bg, (0, 0))
    surface.blit(bird, (bird_x, bird_y))
    pole_x -= 1
    pygame.draw.rect(surface, pole_color, pygame.Rect(pole_x, 0, pole_width, top_pole_height))
    pygame.display.flip()
    pygame.display.update()
    clock.tick(60)`

Pygame 不绘制矩形

1 个答案: