Question

class MM(dict):
    def __init__(self, indexed, *args, **kwargs):
        super(MM, self).__init__(*args, **kwargs) #must do it.
        self['name'] = 'hello, this is a value'
        self.go()

    def go(self, kwargs):
        print kwargs #I want this to print out the kwargs

当我尝试将其初始化时，这个类怎么会产生错误？

>> m = MM()

TypeError: metaMod_Distance() takes exactly 2 arguments (1 given)

Answer 1

您可能想要这样做：

def go(self, **kwargs):
    print kwargs

仅接受关键字参数。因此函数调用将起作用。

此外，您必须将其他内容传递给构造函数（因为未使用的参数indexed）：

m = MM(1) #or whatever

Answer 2

按以下方式修改代码：

class MM(dict):
    def __init__(self, *args, **kwargs):
        super(MM, self).__init__(*args, **kwargs) #must do it.
        self['name'] = 'hello, this is a value'
        print kwargs
        # Or since you class is subclass of dict
        print self

然后

m = MM() #will work

但是如果indexed是你真正需要的属性，那么在创建class时不要忘记为它指定值：

class MM(dict):
    def __init__(self, indexed, *args, **kwargs):
        super(MM, self).__init__(*args, **kwargs) #must do it.
        self['name'] = 'hello, this is a value'
        self.indexed = indexed
        print kwargs
        # Or since you class is subclass of dict
        print self

然后：

indexed = True #since i don't know it's datatype
m = MM(indexed)

Answer 3

错误很简单。你只是一个论点。您需要传入indexed的值。

Answer 4

我不确定你要做什么，但是

__init__有indexed作为参数，您需要在创建对象时指定。

此方法也应该在从 init 调用时发送参数。所以，实际上这不会给你任何问题。

class MM(dict):

    def __init__(self, indexed, *args, **kwargs):
        super(MM, self).__init__(*args, **kwargs) #must do it.
        self['name'] = 'hello, this is a value'
        self.go(kwargs)

    def go(self, kwargs):
        print kwargs #I want this to print out the kwargs

 m = MM('goone')

为什么这个Python方法没有“自我”？

4 个答案: