如何从React useEffect中的另一个函数访问状态

时间:2020-10-12 15:23:34

标签: reactjs typescript react-hooks

const ClientContextProvider = React.memo((props) => {
    const [httpState, dispatchHttp] = useReducer(HttpReducer, initialHttpState())
    const [username, setUsername] = useState(null)
    const [givenName, setGivenName] = useState(null)
    const [surname, setSurname] = useState(null)

    useEffect(() => {
        loadClient();
    }, [])

    const loadClient = () => {
        console.log('Loading client info...')
         const errorMsg = "Error, unable to get logged in client information!";
         const callbacks = {
             [Constants.SUCCESS]:   {   status: OK,
                                    callback: (responseData) => {
                                        setUsername(responseData.username)
                                        setGivenName(responseData.givenName)
                                        setSurname(responseData.surname)
                                        loadAllJobs(username);
                                }}
        };
        axiosGetRequest(process.env.REACT_MYSERVICE_API_USER_LOGIN, errorMsg, dispatchHttp, callbacks);
     }

    const loadAllJobs = (username: string) => {
        if (username === null) {
            console.log('loadAllJobs: username is undefined')
        } else {
        const errorMsg = "Error, unable to get job information for logged in client!";
    
// Function carries on, calls api again using username as part of url

}

我试图在我的loadAllJobs()函数中访问用户名状态。我最初在useEffect中同时具有loadClient()和loadAllJobs()。在loadAllJobs函数中,用户名始终为null,因此我尝试在其上设置一个计时器,使其在7秒钟后运行,以为状态将有时间更新。这也不起作用。现在,我尝试将loadAllJobs函数粘贴到初始函数的回调中,以便在setStates也发生时发生。 这也不起作用,从我的loadAllJobs函数访问时,用户名仍然为null。 任何帮助表示赞赏!

1 个答案:

答案 0 :(得分:1)

  const callbacks = {
    [Constants.SUCCESS]: {
      status: OK,
      callback: responseData => {
        setUsername(responseData.username);
        setGivenName(responseData.givenName);
        setSurname(responseData.surname);
        loadAllJobs(username);
      },
    },
  };

这不能仅仅因为状态更新不同步而起作用。在组件生命周期中的此状态下,用户名仍然为null。它的值将在下一次渲染时更新,但那时为时已晚。

但是为什么要使其变得如此复杂?像这样呼叫loadAllJobs,就可以了:loadAllJobs(responseData.username)