Question

我的数据结构如下：

[
 {title: 'a', washday: 'true', cutday: 'false', colorday: 'true', deepconditionday: 'true'},
 {title: 'b', washday: 'false', cutday: 'true', colorday: 'false', deepconditionday: 'false'},
 {title: 'c', washday: 'true', cutday: 'false', colorday: 'true', deepconditionday: 'true'},
 {title: 'd', washday: 'false', cutday: 'false', colorday: 'false', deepconditionday: 'false'},
]

我的应用程序中还有 cutday ， colorday ， deepconditionday 和 washday 的状态，一个在布尔值true和false之间切换的开关。

如何根据打开的状态过滤上述数据？例如，如果仅启用colorday，则我要显示colorday为“ true”的所有项目。如果将deepconditionday和cutday都打开，那么我要显示出cutday和deepconditionday均为“ true”的所有项目。

谢谢。

Answer 1

可能是这样的：


  let titleFilter = "a";
  let washdayFilter = true;
  let cutdayFilter = true;

  let filteredData = data.filter(
    (datapoint) =>
      datapoint.title == titleFilter &&
      datapoint.washday == washdayFilter.toString() &&
      datapoint.cutday == cutdayFilter.toString()
  );

Answer 2

static func registerSubscriptionWith(ID: String) {
    let predicate = NSPredicate(format: "channelID == %@", ID)
    let subscription = CKQuerySubscription(recordType: "Episode", predicate: predicate, options: .firesOnRecordCreation)
    
    let myContainer = CKContainer.default()
    let publicDatabase = myContainer.publicCloudDatabase
    
    let recordID = CKRecord.ID(recordName: ID)
    publicDatabase.fetch(withRecordID: recordID) { (record, error) in
        if let error = error {
            print("Error: \(error.localizedDescription)")
        } else {
            if record != nil {
                let notification = CKSubscription.NotificationInfo()
                notification.title = record!["channelName"]
                notification.alertBody = record!["caption"]
                notification.soundName = "default"
                
                subscription.notificationInfo = notification
                
                publicDatabase.save(subscription) { result, error in
                    if error != nil {
                        print(error!.localizedDescription)
                    } else {
                        print("Success subscribing user to episode notifications")
                    }
                }
                
            }
        }
    }
}

更多信息在这里： https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

请注意，您使用'true'和'false'作为字符串，而不是布尔值，因此我也这样做。您应该使用布尔值并相应地更改代码 https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Boolean

Answer 3

我已经实现了使用ReactJS和MaterialUI的示例。只需将状态用于开关并按状态过滤即可。链接演示：https://codesandbox.io/s/material-demo-forked-176e3?file=/demo.js

awk 'match($0,/{[^\\]*/){print substr($0,RSTART+1,RLENGTH-1)}' Input_file

如何根据4种条件过滤一组数据？

3 个答案: