我正在尝试使用多个条件过滤List。最主要的是，如果条件为true，则必须使用条件，如果条件为false，则必须使用条件。如果条件为false，则不应使用该条件进行过滤。下面是我的代码
void performFiltering(bool homeVisits, bool onTheSpotServices)
{
//Check for home and on the spot filtering
if(homeVisits==true)
{
filteredOrganizationList = orgList.where((org) => org.homeVisits==true);
}
else if(onTheSpotServices==true)
{
filteredOrganizationList = orgList.where((org) => org.onTheSpotService==true);
}
else if(homeVisits==true && onTheSpotServices==true)
{
filteredOrganizationList = orgList.where((org) => (org.onTheSpotService==true) ||(org.homeVisits==true) );
}
}
在这里，我做了简单的if-else语句。不严重。但是，当有更多条件时，我将无法执行此操作。幸运的是，这仅是两个条件，但我还有很多其他条件。
还请注意，我在上一条语句中使用了OR命令。这意味着获得homeVisits=true或onTheSpotServices=true
处理此问题最有效的方法是什么？
答案 0 :(得分：2)
无需级联多个Host server1
Match user test*
IdentityFile /home/test1/.ssh/id_rsa.test*
相反，使用具有自定义public class App{
Library library = new Library();
//the other stuff
private void run(){
library.addGenres(insertGenreNameHere);
}
}
public class Library{
private Genres[] genres = new Genres[5]; //Obj. Array of genres
private Int nrOfGenres = 0; //number of how many genres there are in an array
public void addGenres(String genreName){ //adds a new genre to the array
if (nrOfGenres < genres.length) {
genres[nrOfGenres] = new Genres(genreName);
nrOfGenres++;
}
else {
System.out.println("You already have the maximum of " + genres.length + " genres!");
}
}
public class Genres {
private String name;
private Books[] books = new Books[5]; //Obj. Array of books
private int nrOfBooks = 0; //number of how many books there are in an array
public Genres(String name) { //Constructor
this.name = name;
}
//getter & setter for the name of the genre
public void addBooks(String titel){ //adds new book to the array
if (nrOfBooks < books.length) {
books[nrOfBooks] = new Books(titel);
nrOfBooks++;
}
else {
System.out.println("You already have the maximum of " + books.length + " books!");
}
}
public void showBooks(){ //prints the books line by line
int x = 0;
while(x < books.length && books[x] != null) {
System.out.println(books[x].getTitle());
x++;
}
}
}
public class Books(){
private String title;
public Books(String title){ //Constructor
this.title = title;
}
//getter & setter for the title
}
函数的单个if-else：
where