Question

我试图获得两天之间的总天数：

1/1/2011
3/1/2011

RETURN
62

可以在SQL Server中执行吗？

Answer 1

PRINT DATEDIFF(DAY, '1/1/2011', '3/1/2011')将为您提供您所追求的目标。

这给出了两个日期之间跨越午夜边界的次数。如果您在计数中包含两个日期，则可能决定需要添加一个 - 或者如果您不想包含任何一个日期，则减去一个日期。

Answer 2

SQL Server DateDiff

DECLARE @startdate datetime2 = '2007-05-05 12:10:09.3312722';
DECLARE @enddate datetime2 = '2009-05-04 12:10:09.3312722'; 
SELECT DATEDIFF(day, @startdate, @enddate);

Answer 3

请参阅DateDiff：

DECLARE @startdate date = '2011/1/1'
DECLARE @enddate date = '2011/3/1'
SELECT DATEDIFF(day, @startdate, @enddate)

Answer 4

您可以尝试此MSDN link

DATEDIFF ( datepart , startdate , enddate )
SELECT DATEDIFF(DAY, '1/1/2011', '3/1/2011')

Answer 5

另一种日期格式

select datediff(day,'20110101','20110301')

Answer 6

SELECT DATEDIFF(day, '2005-12-31 23:59:59.9999999', '2006-01-01 00:00:00.0000000');

Answer 7

如果你想做同样的事情存储过程，那么你需要应用下面的代码。

select  (datediff(dd,'+CHAR(39)+ convert(varchar(10),@FromDate  ,101)+ 
 CHAR(39)+','+CHAR(39)+ convert(varchar(10),@ToDate  ,101) + CHAR(39) +')) 
 Daysdiff

其中@fromdate和@todate是SP的参数

Answer 8

这对我有用-

SELECT DATEDIFF(DAY, startdate, enddate) AS DayCount

Example : SELECT DATEDIFF(DAY, '11/30/2019', GETDATE()) AS DayCount

Answer 9

DECLARE @FDate DATETIME='05-05-2019' /*This is first date*/
 GETDATE()/*This is Current date*/
SELECT (DATEDIFF(DAY,(@LastDate),GETDATE())) As DifferenceDays/*this query will return no of days between firstdate & Current date*/

SQL SERVER：获取两个日期之间的总天数

9 个答案: