我很陌生。 我需要在此查询的单独列中以天为单位进行区分 在t.1start和t1.finish之间。
谢谢,路易
SELECT ROW_NUMBER() OVER(ORDER BY TOWN) AS 'row',
T1.Surname,
T1.Forename,
T1.Town,
T1.Description,
T1.Sex,
T1.DOB,
T1.start,
T1.finish,
FROM dbo.viewServiceContractFull T1
WHERE
T1.finish>='2013/01/01'
and
T1.finish<='2013/01/31'
我现在如何只查询某些城镇?
答案 0 :(得分:1)
在SQL Server中,您可以使用
SELECT DATEDIFF (MyUnits, '2010-01-22 15:29:55.090', '2010-01-22 15:30:09.153')
答案 1 :(得分:0)
您可以使用DATEDIFF功能确定两个日期之间的间隔,您可以使用CAST/CONVERT将字符串日期转换为实际日期(如果需要),例如:
CAST('2010-01-22 15:29:55.090' AS DATETIME)
使用CONVERT功能可以选择日期的格式。
答案 2 :(得分:0)
SELECT ROW_NUMBER() OVER(ORDER BY TOWN) AS 'row',
T1.Surname,
T1.Forename,
T1.Town,
T1.Description,
T1.Sex,
T1.DOB,
T1.start,
T1.finish, cast(DATEDIFF(DAY,T1.start,T1.finish) as varchar) as difference
FROM dbo.viewServiceContractFull T1
WHERE
T1.finish>='2013/01/01'
and
T1.finish<='2013/01/31'
另请查看this