Question

select  count(distinct(dateadd(d, 0, datediff(d, 0,checktime)))) as workingdays
from departments,
 dbo.USERINFO INNER JOIN dbo.CHECKINOUT ON 
     dbo.USERINFO.USERID = dbo.CHECKINOUT.USERID
where  userinfo.name='Gokul Gopalakrishnan' and deptname='GEN/SUP-TBL' 
and checktime>='2014-05-01' and checktime<='2014-05-30'

从上面的代码中我可以找到两个日期之间员工的总工作日。

workingdays
20

但现在我想要其他列名称的总工作日。我想计算两个日期之间的总工作日。

workingdays  businessdays
20              21

我该怎么做？

Answer 1

如果您只想排除周末，那么您只需添加以下内容即可使用条件计数排除这些：

count(distinct case when datepart(weekday, getdate()) <= 5 then date end)

所以你的查询变为：

set datefirst 1;

select  count(distinct(dateadd(d, 0, datediff(d, 0,checktime)))) as workingdays,
        count(distinct case when datepart(weekday, getdate()) <= 5 
                            then dateadd(d, 0, datediff(d, 0,checktime)) 
                        end) as weekdays
from departments,
 dbo.USERINFO INNER JOIN dbo.CHECKINOUT ON 
     dbo.USERINFO.USERID = dbo.CHECKINOUT.USERID
where  userinfo.name='Gokul Gopalakrishnan' and deptname='GEN/SUP-TBL' 
and checktime>='2014-05-01' and checktime<='2014-05-30'

HOWEVER 我真的建议您在数据库中添加calendar table。它使一切变得如此简单，您的查询将成为：

SELECT  DaysWorked = COUNT(cio.Date),
        WeekDaysWorked = COUNT(CASE WHEN c.IsWeekDay = 1 THEN cio.Date END),
        WorkingDaysWorked = COUNT(CASE WHEN c.IsWorkingDay = 1 THEN cio.Date END),
        TotalDays = COUNT(*),
        TotalWeekDays = COUNT(CASE WHEN c.IsWeekDay = 1 THEN 1 END),
        TotalWorkingDays = COUNT(CASE WHEN c.IsWorkingDay = 1 THEN 1 END)
FROM    dbo.Calender AS c
        LEFT JOIN
        (   SELECT  DISTINCT
                    Date = CAST(CheckTime AS DATE)
            FROM    dbo.Departments AS d
                    CROSS JOIN dbo.userInfo AS ui
                    INNER JOIN dbo.CheckInOut AS cio
                        ON cio.UserID = ui.UserID
            WHERE   ui.Name = 'Gokul Gopalakrishnan' 
            AND     d.deptname = 'GEN/SUP-TBL' 
        ) AS cio
            ON c.Date = cio.Date
WHERE   d.Date >= '2014-05-01'
AND     d.Date <= '2014-05-30';

通过这种方式，您可以定义公共假日，周末等。它比任何其他解决方案都更加灵活。

编辑

我想我误解了你原来的标准。这应该适用于没有日历表的地方：

SET DATEFIRST 1;

DECLARE @StartDate DATE = '2014-05-01', 
        @EndDate DATE = '2014-05-30';

DECLARE @Workdays INT = 
    (DATEDIFF(DAY, @StartDate, @EndDate) + 1)
    -(DATEDIFF(WEEK, @StartDate, @EndDate) * 2)
    -(CASE WHEN DATEPART(WEEKDAY, @StartDate) = 7 THEN 1 ELSE 0 END)
    -(CASE WHEN DATEPART(WEEKDAY, @EndDate) = 6 THEN 1 ELSE 0 END);


SELECT  WorkingDays = COUNT(DISTINCT CAST(CheckTime AS DATE)),
        BusinessDays = @Workdays
FROM    dbo.Departments AS d
        CROSS JOIN dbo.userInfo AS ui
        INNER JOIN dbo.CheckInOut AS cio
            ON cio.UserID = ui.UserID
WHERE   ui.Name = 'Gokul Gopalakrishnan' 
AND     d.deptname = 'GEN/SUP-TBL' 
AND     cio.CheckTime >= @StartDate
AND     cio.CheckTime <= @EndDate;

Answer 2

以下查询计算@FromDate和@ToDate变量之间的星期五计数

((DATEDIFF(DAY,@FromDate,@ToDate)-(6-DATEPART(dw,@FromDate)))/7)*2

以下查询计算工作日计数和工作日计数至今：

DECLARE @FromDate DATE = '2014-05-01',
    @ToDate DATE = '2014-05-30'

SELECT  COUNT(DISTINCT CAST(checktime AS Date)) as workingdays,
        DATEDIFF(DAY,@FromDate,@ToDate) -
       ((DATEDIFF(DAY,@FromDate,@ToDate)-(6-DATEPART(dw,@FromDate)))/7)*2 AS BusinessDay
from departments,
 dbo.USERINFO INNER JOIN dbo.CHECKINOUT ON 
     dbo.USERINFO.USERID = dbo.CHECKINOUT.USERID
where  userinfo.name='Gokul Gopalakrishnan' and deptname='GEN/SUP-TBL' 
and checktime>= @FromDate and checktime<=@ToDate

计算两个日期之间的总业务工作日

2 个答案: