说明：

Question

在Python中进行编程时，我陷入了while循环即使在满足条件之后也没有终止的情况下陷入困境的情况

代码如下：

print('--- Alex\'s Calculator ---')
print('1. ADDition')
print('2. SUBstraction')
print('3. MULtiply')
print('4. DIVide')
print('5. EXIT')
x = int(input())

command = ' Enter Your Two numbers To Perform The Operation : '
def ini():
    a = int(input())
    b = int(input())
    return a, b
def resultoo():
    result = ' Your Result after Performing The Operation from {} and {} is {}'
    print(result.format(a,b,c))
    print(' Want To Continue If Yes then Enter Your Choice else Press any number exept 1 - 4')
    x = int(input())

while x < 5:
    if x == 1:
        print(command)
        a, b = ini()
        c = a + b
        resultoo()
    elif x < 5:
        break

Answer 1

正如注释中指定的kuro一样，您的while循环看不到x，因为x在resultoo（）中是本地的。

要轻松解决，只需添加：

return x

在resultoo（）结尾

和

x = resultoo()

在while循环中

Answer 2

您可以对此使用global var，更改此：

def resultoo():
    result = ' Your Result after Performing The Operation from {} and {} is {}'
    print(result.format(a,b,c))
    print(' Want To Continue If Yes then Enter Your Choice else Press any number exept 1 - 4')
    x = int(input())

进入：

def resultoo():
    global x
    result = ' Your Result after Performing The Operation from {} and {} is {}'
    print(result.format(a,b,c))
    print(' Want To Continue If Yes then Enter Your Choice else Press any number exept 1 - 4')
    x = int(input())

说明：

x是一个全局参数，在函数闭包之外是相同的，但不在函数内部，函数具有它自己的参数，因此，如果要更改在外部初始化的全局参数该函数，则需要先调用global语句，这将使x成为全局x

Answer 3

输入选项5后，您要退出。

我加了

import sys

并更改

elif x < 5:

到

elif x == 5:

并添加

sys.exit(0)

我还添加了getMenu（）函数

这是在我的编辑器中运行的完整代码：

import sys


def ini():
    command = ' Enter Your Two numbers To Perform The Operation : '
    print(command)
    a = int(input())
    b = int(input())
    return a, b


def resultoo(a, b, c):
    result = ' Your Result after Performing The Operation from {} and {} is {}'
    print(result.format(a, b, c))


def getMenu(x):
    if x == 0:
        print("Choose menu item")
        x = int(input())
    elif x != 0:
        print(' Want To Continue If Yes then Enter Your Choice else Press any number exept 1 - 4')
        x = int(input())

    return x


def main():
    x = 0
    while x < 5:
        print('\n\n1. ADDition')
        print('2. SUBstraction')
        print('3. MULtiply')
        print('4. DIVide')
        print('5. EXIT\n')

        x = getMenu(x)

        if x == 1:
            a, b = ini()
            c = a + b
            resultoo(a, b, c)

        elif x == 5:
            sys.exit(0)

        else:
            print("No valid menu item")


if __name__ == '__main__':
    print('----------------------------------------------------------------------------------------------------------')
    print('-------------------------------------------- Alex\'s Calculator -------------------------------------------')
    main()

我还格式化了您的代码（Pycharm中的alt + Enter）以符合PEP8标准；）

当条件满足时，while循环不会终止

3 个答案:

说明：